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Andre45 [30]
3 years ago
14

Find the area of the parallelogram with vertices k(1, 1, 1), l(1, 3, 2), m(5, 8, 2), and n(5, 6, 1).

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0
The area can be found as the magnitude of the cross product of the vectors representing two adjacent sides.
  area = || kl × kn || = || (0, 2, 1) × (4, 5, 0) ||
    = || (-5, 4, -8) || = √105


_____
For the purpose here, kl = l - k = (1, 3, 2) - (1, 1, 1) = (0, 2, 1)
and nk = n - k = (5, 6, 1) - (1, 1, 1) = (4, 5, 0)

The cross product can be calculated using a suitable calculator. By hand, it is the determinant
\left|\begin{array}{ccc}i&j&k\\0&2&1\\4&5&0\end{array}\right|
where i, j, k are unit vectors in the x, y, z directions.
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The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

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Step-by-step explanation:

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