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koban [17]
3 years ago
5

For f(x) = 3x + 1 and g(x) = x2 - 6, find (f + g)(x).

Mathematics
1 answer:
alexdok [17]3 years ago
8 0
(3x + 1) + (x2 - 6)
x2 + 3x - 5
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For f(x) = 3x+1 and g(x) = x^2-6, find (g/f)(x)
nexus9112 [7]
G/f(x) = x^2 - 6 / 3x + 1
3x + 1 = x^2 - 6
x^2 - 3x - 6 - 1 = 0
x^2 - 3x - 7 = 0
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4 0
3 years ago
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Solve for c.<br> 55c+13 &lt; 750 +39
iren [92.7K]

Answer:

c = anything less than 14.1

Step-by-step explanation:

55c+13 < 750 + 39

55c+13 < 789

55c < 776

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Hope It Helps

5 0
2 years ago
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Answer: 108$

Step-by-step explanation:

5 0
3 years ago
tres hermanos danvueltas circuito en bicicleta. el mayor tarda 18 en dar Una vuelta el del medio 24 minutos yel menos 36 minutos
hodyreva [135]
Tienes que hallar el mínimo común múltiplo de las 3 cantidades.

18= 2×3²
24= 2³×3
36= 2²×3²

mcm(18,24,36) = 2³×3²=8×9= 72

Eso quier decir que si partieron a la misma hora se encontraran  de nuevo en el punto de partida 72 minutos después de la salida.

Las vueltas que habrán realizado será el resultado de dividir 72 entre el tiempo que tardan en dar una vuelta

<span>Mayor: </span>  = 4

<span>Mediano: </span>  = 3

<span>Pequeño: </span>  =  2

Soluciónes:

se vuelven a encontrar a los 72 min de la salida
<span>El mayor dió 4 vueltas, el mediano 3 y el pequeño 2</span>
6 0
2 years ago
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Answer:

b

Step-by-step explanation:

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2 years ago
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