Answer:
12x³+89x²-261x (?)
Step-by-step explanation:
For this equation, I am going to assume you want to find the value of the expression and you're multiplying all the values (since you can't find the value of x with this unless you had an equation).
(x)(4x-9)(3x+29)
(4x²-9x)(3x+29)
12x³+89x²-261x
y = ( 48 *2 ) / 6
Step-by-step explanation:
If y varies directly as x they are directly proportional, which means they relate to each other in the same way....
2 : y = 6: 48
what is y if x = 2?
The value of y can be found if you write it a two fracrions
2 : y = 6 : 48
2 / y = 6 / 48
cross multiply the fractions gives
6*y = 48 *2
divide left and right of the = sign by 6 gives the answer:
y = ( 48 *2 ) / 6
(if you solve it you get y = 12 but that was not the question).
Other method:
multiply left and right of the = sign by y
2 * y/y = y *6 / 48
6y / 48 = 2 * 1
multiply left and right of the = sign by 48
6y * 48/48 = ( 48 *2 )
6y = ( 48 *2 )
divide left and right of the = sign by 6
6/6* y = ( 48 *2 )/6
y = ( 48 *2 ) / 6
(if you solve it you get y = 12 but that was not the question).
So to solve this question, your goal is to find out how the way it is solved is not correct.
Your answer would be: On the third line, the student adds the 8 to both sides instead of subtracting. The way the initial equation is given is
y-(-8)=-6(x-2). After distributing the six, the student should make the 8 positive because subtracting a negative makes a positive. After solving, the equation should look like: y(+8)=-6x+12, so you would subtract the 8 from both sides instead of adding it, and solve from there.
Eighths and their multiples are common fractions which I recommend memorizing, but to actually solve this, you use the literal meaning of a fraction and divide 5 by 8. See the long-division below (it was surprisingly difficult to type, so I hope it helps!).
To round 0.625 to the nearest hundredth, we go to the second decimal place, which is 5, so we round up to 0.63.
Answer:
9 yards
Step-by-step explanation:
multiply the length of the cloth by the length used for bedsheet
