CAN SOMEONE HELP ME WITH MY QUESTION PLS?

Mathematics

1 answer:

Oksana_A [137]4 years ago

5 0

Answer:

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Step-by-step explanation:

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Show me and example of a multi step equation and solve.

Maru [420]

problemSolve 6x + 5 = 10 + 5x. Check your solution. This equation has x terms on both the left and the right. To solve an equation like this, you must first get the variables on the same side of the equal sign. You can subtract 5x on each side of the equal sign, which gives a new equation: x + 5 = 10. This is now a one-step equation! Subtract 5 from both sides.Check Check your solution by substituting 5 for x in the original equation. This is a true statement, so the solution is correct.Answerx = 5

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4 years ago

According to a 2009 Reader's Digest article, people throw away approximately 11% of what they buy at the grocery store. Assume t

expeople1 [14]

Answer:

0.14% probability that the sample proportion exceeds 0.2

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .