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2 years ago

Help me pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics

1 answer:

yaroslaw [1]2 years ago

7 0

Answer:

The answer is 4z^2 + 7z

Step-by-step explanation:

7z + 4z^2 +6 - 6

So, just combine like term which is 6 - 6 = 0

So, the remaining is 4z^2 + 7z that cannot be simplified anymore

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What is square root of 167?

enot [183]

The square root of 167 would be 12.922847. If you need it rounded to the nearest tenth it would be 12.9

If you need t rounded to the nearest hundredth, it would be 12.92.

Hope this helps :)

7 0

3 years ago

If m, p, and t are distinct positive prime numbers, then (m^3)(p)(t) has how many different positive factors greater than 1?

harina [27]

Answer:

d. 15

Step-by-step explanation:

List the exponents of each of the prime factors. Here, they are 3, 1, 1.

Add 1 to each of these values and form the product of these sums:

(4)(2)(2) = 16

This is the number of divisors of the number. Since 1 is included in this count, 15 of the divisors are greater than 1.

3 0

3 years ago

Help diffrent question

Scorpion4ik [409]

Answer:

is congruent because are parralel

4 0

3 years ago

Find the distance between (4,-3),(3,-8)

WARRIOR [948]

So you just have to use distance formula

8 0

3 years ago

Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+

Hoochie [10]

The vertex form of the equation of a parabola is given by

$y-k=a(x-h)^2$

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

$y-(-2)=a(x-(-12))^2 \\ \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\ \\ y=ax^2+24ax+114a-2 \\ \\ y=x^2+24x+ \frac{114a-2}{a}$

For a = 1,

$y=x^2+24x+112$

<span>The parabola whose minimum is at (−12,−2) is given by the equation $y=x^2+ax+b$ , where a = 24 and b = 112.</span>

8 0

3 years ago