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patriot [66]
2 years ago
14

Help me pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
yaroslaw [1]2 years ago
7 0

Answer:

The answer is 4z^2 + 7z

Step-by-step explanation:

7z + 4z^2 +6 - 6

So, just combine like term which is 6 - 6 = 0

So, the remaining is 4z^2 + 7z that cannot be simplified anymore

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Evaluate the determinant for the following matrix: [-5 1, 1 4]
MrRissso [65]
The matrix given is \left[\begin{array}{ccc}-5&1\\1&4\end{array}\right]

To find determinant \left[\begin{array}{ccc}a&b\\c&d\end{array}\right] we do ad-bc

So, the determinant of the given matrix is
(-5)(4)-(1)(4) = -20 - 4 = -24
4 0
3 years ago
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The lengths of two sides of a triangle are 12 ft and 13 ft. find the range of possible lengths for the third side
mihalych1998 [28]
Let x be the length of third side.
12 + x > 13
x > 1-------------(1)
13 + x > 12
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3 years ago
Find the Volumes?<br> I need help with both of these, please!!!
Arada [10]

Answer:

1. 36

2. 5390

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4 0
3 years ago
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Which of the following statements is true?
sdas [7]

Answer:

Option The product of (-x+4)(x^2+3x-3) is

-x^3+x^2+15x-12 is correct.

That is (-x+4)(x^2+3x-3)=-x^3+x^2+15x-12

Step-by-step explanation:

Given expression is (-x+4)(x^2+3x-3)

To find the product of the given expression :

(-x+4)(x^2+3x-3)

( By using the distributive property each term in the factor is multiplied by each term in the another factor )

=[-x(x^2)+(-x)(3x)+(-x)(-3)]+[4(x^2)+4(3x)+4(-3)]

=-x^3-3x^2+3x+4x^2+12x-12 ( adding the like terms )

=-x^3+x^2+15x-12

Therefore (-x+4)(x^2+3x-3)=-x^3+x^2+15x-12

Therefore Option The product of

(-x+4)(x^2+3x-3) is -x^3+x^2+15x-12 is correct.

That is (-x+4)(x^2+3x-3)=-x^3+x^2+15x-12

7 0
3 years ago
5-5+x*7=14<br><br> What is x=
Novosadov [1.4K]
0+x*7=14
X=2 is the correct answer
8 0
3 years ago
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