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docker41 [41]
3 years ago
14

Exponential form of log4 4=1

Mathematics
1 answer:
vlabodo [156]3 years ago
4 0
4^1= 4. the exponential form is b^e=n, while log is logb n=1.
You might be interested in
Max z = 3x1 + 5x2 subject to: 7x1 + 12x2 ≤ 136 3x1 + 5x2 ≤ 36 x1, x2 ≥ 0 and integer find the optimal solution. what is the valu
Reptile [31]
The second constraint is the same as the objective function, so your problem boils down to finding integer solutions to
.. 3x1 +5x2 = 36

There are 3 solutions. They are (x1, x2) = (12, 0), (7, 3), (2, 6)

The value of the objective function there is (obviously) 36.
4 0
3 years ago
11 5/9 + 10 1/3 plz help
Likurg_2 [28]
10 1/3= 31/3
31/3= 93/9

11 5/9= 104/9
93/9 + 104/9 = 197/9
197/9= 21 8/9



your answer is 21 & 8/9


Good Luck
XD
7 0
3 years ago
If you have a decimal answer, round to the nearest tenth!<br> x/-4−3=0
lions [1.4K]
X = -12 !!

so first rewrite the fraction
multiply both sides
move the constant to the right
change the signs
then you have your solution
5 0
3 years ago
Maria is 12 years older than Jose. In 9 years Maria will be twice as old as Jose.
Stella [2.4K]
I would have to say
Maria is 21
Jose 9
If Maria was 12 and Jose wasn’t born yet look at their ages in nine years.
Hope this helped.
5 0
3 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
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