Answer:
309 feet
Step-by-step explanation:
given that the height can be represented by a quadratic equation, we can say that the general form of the equation will look something like this:
h(x) = Ax² + Bx + C
we know that at the starting point of the launch that time = 0 (i.e x = 0) and hence h (x) = 0, if we substitute this into our equation, we can find the value for C
h(0) = A(0)² + B(0) + C = 0
C = 0
Hence the equation becomes
h(x) = Ax² + Bx
Given when x = 1, h(1) = 121,
121 = A(1)² + B(1)
A + B = 121 ------> eq 1
Given when x = 2, h(2) = 224,
224 = A(2)² + B(2)
4A + 2B = 224 (divide both sides by 2)
2A + B = 112------> eq 2
Solving the system of equations which comprise eq 1 and eq 2 using your favorite method, we end up with A = -9 and B = 130
our equation becomes:
h(x) = -9x² + 130x
when x = 3
h(3) = -9(3)² + 130(3) = 309 feet
Move your cursor man it’s covering a critical value needed to answer
The answer is 25.
Have a good night
The new graph will go down 4 point so y coordinate will go down 4. (-6,5) becomes ( -6, 1)
Answer: The answer is D
Step-by-step explanation:
If you read all the answers only D is true
