The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
Answer:
(A-c)/8 = b
Step-by-step explanation:
A = 8b +c
A - c = b
(A-c)/8 = b
Hope this helps you!
Answer:
140$
Step-by-step explanation:
You can use the three rule step.
20% ?
-------=------------
100%. 700$
Then u go 20 x 700 divided by 100 which gives you the 20% in $
Answer:
unlike terms
Step-by-step explanation:
since the first 9y is squared they cannot be combined since the other isn't squared, they cannot be simplified, nor are they alike
