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viktelen [127]
3 years ago
5

Help plz:)))I’ll mark u Brainliest

Mathematics
1 answer:
Lelu [443]3 years ago
3 0
20^2=10^2+2√39^2
400=100+12.49
400=112.49
means c^2>a^2+b^2
so the answer is an obtuse triangle
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Step-by-step explanation:

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How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

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Assoli18 [71]

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fomenos

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Step-by-step explanation:

Perpendicular lines: Their gradients are reciprocals.

This means:

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Gradient of the given equation is 3.

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Gradient of the equation we're finding is -1/3

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3 0
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