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Allushta [10]
3 years ago
6

Help Please I'm Out Of Time ;(

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

Total area = 31.5 unit²

Step-by-step explanation:

Assume 1 block = 1 unit²

Divide diagram into 3 part

1. 5 by 5 block square

2. 2 by 2 block triangle(1)

2. 3 by 3 block triangle(2)

Area of square = side × side

Area of square = 5 × 5

Area of square = 25 unit²

Area of triangle(1) = [1/2][base][height]

Area of triangle(1) = [1/2][2][2]

Area of triangle(1) = 2 unit²

Area of triangle(2) = [1/2][base][height]

Area of triangle(2) = [1/2][3][3]

Area of triangle(2) = 4.5 unit²

Total area = Area of square + Area of triangle(1) +Area of triangle(2)

Total area = 25 unit² + 2 unit² + 4.5 unit²

Total area = 31.5 unit²

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Can someone please help me on this one.
zvonat [6]
The answer is choice C

The angles GQI and IQM combine to form the straight angle GQM which is 180 degrees. This angle is essentially a straight line. It is the line GM. 
5 0
3 years ago
The value of k is: <br><br> please help im struggling
iVinArrow [24]

Answer:

  • E) 48

Step-by-step explanation:

<em>Parallel lines divide the transversals proportionally.</em>

Set proportions and solve for k:

  • k/24 = 64/32
  • k/24 = 2
  • k = 24*2
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Correct choice is E.

4 0
2 years ago
Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

6 0
3 years ago
The area of a rectangular field is 8342 yd2 . if the width of the field is 86 yards, what is its length?
Irina18 [472]
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Answer:

...

Step-by-step explanation:

...

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3 years ago
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