Lisa invests $4,000 in two types of bonds, bond A and bond B. Bond A offers a 10% return, and bond B offers a 6% return. Lisa in
vests $x in bond A and $y in bond B. Her total return on the investment is $340. The system of linear equations defining the situation is x+y=4,000 and .1x=.06y=340. The amount Lisa invested at the rate of 10% is ___ , and the amount she invested at the rate of 6% is ___ .
Lisa invests $4,000 in two types of bonds, bond A and bond B.
A + B = 4000
Bond A offers a 10% return, and bond B offers a 6% return.
.10 A + .06 B = 340
Her total return on the investment is $340. <span>since the relationship A+B=4000 must satisfy the setup for all values A and B
we can state that A = 2000 + n, and B = 2000 -n
afterall: 2000 +n + 2000 - n = 4000 for all n
.10(2000+n) + .06(2000-n) = 340, once we know n we know A and B</span>
