Solution: (-Infinite, -8/3] U (4, Infinite)
Using that a fraction is greater than or equal to zero when the numerator and denominator have the same sign:
a/b>=0. Then we have two cases:
Case 1) If the numerator is positive, the denominator must be positive too (at the same time):
if a>=0 ∩ b>0
Or (U)
Case 2) If the numerator is negative, the denominator must be negative too (at the same time):
if a<=0 ∩ b<0
In this case a=3x+8 and b=x-4, then:
Case 1):
if 3x+8>=0 ∩ x-4>0
Solving for x:
3x+8-8>=0-8 ∩ x-4+4>0+4
3x>=-8 ∩ x>4
3x/3>=-8/3 ∩ x>4
x>=-8/3 ∩ x>4
Solution Case 1: x>4 = (4, Infinite)
Case 2):
if 3x+8<=0 ∩ x-4<0
Solving for x:
3x+8-8<=0-8 ∩ x-4+4<0+4
3x<=-8 ∩ x<4
3x/3<=-8/3 ∩ x<4
x<=-8/3 ∩ x<4
Solution Case 2: x<=-8/3 = (-Infinite, -8/3]
Solution= Solution Case 1 U Solution Case 2
Solution = (4, Infinite) U (-Infinite, -8/3]
Solution: (-Infinite, -8/3] U (4, Infinite)
Answer:
17.872, 8
Step-by-step explanation:
Chords that pass through the center are the diameter, and lines that are tangent to the circle are perpendicular to the diameter at that point.
Therefore, what we are looking at are right triangles, and we can find the distance using Pythagorean theorem.
c² = a² + b²
(19.5)² = (7.8)² + b²
b ≈ 17.872
c² = a² + b²
(10)² = (6)² + b²
b = 8
01101000 01101001 00100000 01100110 01110010 01101001 01100101 01101110 01100100
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Thus the correct answer is (( B )) .
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Step-by-step explanation:
First of all, we will find the solution of the given equation
So,
Given equation is:
Adding 6m on both sides
Dividing both sides by 9
In order to check, if the solution is the solution of given options, we will put the solution in the equation, if both sides of equations are equal then the solution belongs to the equation.
So,
For 
Putting m=4
For 
Putting m=4
![-2[-4(4)-6.4]=44.8\\-2(-16-6.4) = 44.8\\-2(-22.4) = 44.8\\44.8 = 44.8](https://tex.z-dn.net/?f=-2%5B-4%284%29-6.4%5D%3D44.8%5C%5C-2%28-16-6.4%29%20%3D%2044.8%5C%5C-2%28-22.4%29%20%3D%2044.8%5C%5C44.8%20%3D%2044.8)
For 
Putting m=4
for 
Putting m = 4
Keywords: Equations, linear equation
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