La raíz cuadrada de 3 es 1.73
Answer:
42 units^2.
Step-by-step explanation:
We are given that it is a rectangle so its area is the product of the length of adjacent sides.
Length of the horizontal line = 11 - 4 = 7 units ( from the first 2 points) and the length of an adjacent side is 9 - 3 = 6 units (from the second and third points).
Area = 7 * 6 = 42.
Points:
Quadrant I: (+, +)
Quadrant II: (-, +)
Quadrant III: (-, -)
Quadrant IV: (+, -)
Thus the point (5,4) is found in Quadrant I.
Option C
The ratio for the volumes of two similar cylinders is 8 : 27
<h3><u>
Solution:</u></h3>
Let there are two cylinder of heights "h" and "H"
Also radius to be "r" and "R"
![\text { Volume of a cylinder }=\pi r^{2} h](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Volume%20of%20a%20cylinder%20%7D%3D%5Cpi%20r%5E%7B2%7D%20h)
Where π = 3.14 , r is the radius and h is the height
Now the ratio of their heights and radii is 2:3 .i.e
![\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Br%7D%7D%7BR%7D%3D%5Cfrac%7B%5Cmathrm%7Bh%7D%7D%7BH%7D%3D%5Cfrac%7B2%7D%7B3%7D)
<em><u>Ratio for the volumes of two cylinders</u></em>
![\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%201%7D%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%202%7D%3D%5Cfrac%7B%5Cpi%20r%5E%7B2%7D%20h%7D%7B%5Cpi%20R%5E%7B2%7D%20H%7D)
Cancelling the common terms, we get
![\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%201%7D%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%202%7D%3D%5Cleft%28%5Cfrac%7B%5Cmathrm%7Br%7D%7D%7BR%7D%5Cright%29%5E%7B2%7D%20%5Ctimes%5Cleft%28%5Cfrac%7B%5Cmathrm%7Bh%7D%7D%7B%5Cmathrm%7BH%7D%7D%5Cright%29)
Substituting we get,
![\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%201%7D%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%202%7D%3D%5Cleft%28%5Cfrac%7B2%7D%7B3%7D%5Cright%29%5E%7B2%7D%20%5Ctimes%5Cleft%28%5Cfrac%7B2%7D%7B3%7D%5Cright%29)
![\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%201%7D%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%202%7D%3D%5Cfrac%7B2%20%5Ctimes%202%20%5Ctimes%202%7D%7B3%20%5Ctimes%203%20%5Ctimes%203%7D)
![\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%201%7D%7B%5Ctext%20%7BVolume%20of%20cylinder%20%7D%202%7D%3D%5Cfrac%7B8%7D%7B27%7D)
Hence, the ratio of volume of two cylinders is 8 : 27
Answer:
The new length is 13.5 meters
Step-by-step explanation:
Here, we are interested in calculating the new length of the cloth she wants to use
What we know from the question is that she is making a reduction of 10% from an initial of 15 meters
Thus, the length she is to use can be calculated by first getting what 10% of 15 meters is
Mathematically, that would be ;
10/100 * 15 = 1.5 meters
We now subtract this from the total of 15 meters
= 15 meters - 1.5 meters = 13.5 meters