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3 years ago

at hoffman's bike rental, it costs $35 to rent a bike for 9 hour. How many dollars does it cost per hour of bike use?

Mathematics

2 answers:

Jet001 [13]3 years ago

6 0

Answer:

Step-by-step explanation:

35 for 9 hours

35 / 9 = 3.88888889, about 3.89 per hour

Galina-37 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

This is a straight forward proportion.

9 hours = 35 dollars

1 hour = x

9:1::35:x Cross multiply

9 hour * x = 1 hour * 35 dollars. Divide by 9

9 hour / 9 hour x = 1 hour 35 dollars/9 hour

x = 35/9

x = $3.89 rounded.

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Answer:

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Step-by-step explanation:

We are given that DE

$(tanx-sinx siny)dx+cosxcosydy=0$

We have to determine given DE is exact or not.

Compare it with Mdx+Ndy=0

$M=tanx-sinx siny$

$N=cosxcosy$

$\frac{\partial M}{\partial y}=$ $M_y=-sinxcosy$

$\frac{\partial N}{\partial x}=N_x=-sinxcosy$

Therefore, $M_y=N_x$

If DE is exact then $M_y=N_x$

Hence,it is exact.

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Integrate w.r.t x on both sides

$f(x,y)=\int(tanx-sinxsiny)dx$

$f(x,y)=lnsecx+cosxsiny+\phi(y)$ ...(1)

By using the formula

$\int tanxdx=lnsecx+C,\int sinxdx=-cosx+C$

Differentiate partially equation (1) w.r.t y

$\frac{\partial f}{\partial y}=cosxcosy+\phi'(y)$

By using the formula:

$\frac{d(sinx)}{dx}=cosx$

$N=\frac{\partial f}{\partial y}=cosxcosy=cosxcosy+\phi'(y)$

$\phi'(y)=cosxcosy-cosxcosy=0$

$\phi'(y)=0$

Integrate w.r.t y

$\phi(y)=C$

Substitute the value

$f(x,y)=ln secx+cosx siny+C$

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