Triangles have common side AC, and 2 adjacent to this side corresponding angles.
∠BAC=∠DCA, and
∠ACB=∠SAD.
So, triangles <span>ABC and ADC are congruent by ASA.</span>
Answer:
False
Step-by-step explanation:
4x + y < 2
y > –2
Substitute the point into the inequalities and see if they are true
4(4) + 2 < 2
16+2 < 2
18 <2 False
2 > –2 True
Since one is false the point is not a solution
-2(5y - 5) - 3y < = -7y + 22
-10y + 10 - 3y < = -7y + 22
-13y + 10 < = -7y + 22
-13y + 7y < = 22 - 10
-6y < = 12
y > = -12/6
y > = -2....answer B
Answer:
15.0
Step-by-step explanation:
Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.
The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)
