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Feliz [49]
3 years ago
9

The ratio of boys to girls at a concert is 13:17. If there are a total of 90 children at the concert, how many boys are at the c

oncert?
Mathematics
1 answer:
Gwar [14]3 years ago
6 0
Their is 40 boys at the concert
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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
Bond [772]

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }

.

.

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }

.

.

.

Following the pattern, we can see that for f^{n}(x),

f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} }  \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}

This applies for n ≥ 1, Expressing f(x) in summation, we have

\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}

Combining ln2 with the rest of series, we have

f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0
2 years ago
According to the line plot, what is the total weight gained by the dogs that gained 1/8 f a pound or 3/4 of a pound?
erik [133]

3 1/8

First you take the all the dogs that gained 3/4 (which is 4)
Then you multiply it by 4

3/4x4=3
Then you add the dogs that gained 1/8 of a pound

3+1/8=3 1/8

4 0
2 years ago
How do you write the indicated form of a function for an absolute value equation?
timama [110]
Attached solution and work.

3 0
3 years ago
Samuel was riding in the back seat of the station wagon on the way home after a long and tiring day at the
Anon25 [30]

Answer:

Samuel slept for 1/4 of the distance.

Step-by-step explanation:

The information provided are:

  • Samuel fell asleep halfway home.
  • He didn't wake up until he still had half as far to go as he had already
  • gone while asleep.

Consider that the total distance covered was 1.

Then from the first point we know that Samuel fell asleep after covering a distance of 1/2.

It is provided that he woke up only after covering half of the remaining distance.

That is, he slept for 1/4 of the remaining distance.

Thus, Samuel was asleep for 1/4th of the entire trip home.

6 0
3 years ago
Look at picture please !! I really need help thank you !
aksik [14]
I think it’s c if not i’m sorry i got you incorrect but it just makes more since
5 0
2 years ago
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