Answer:
B its B
Step-by-step explanation:
Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.
Let x be the height of the flagpole, then
Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>
Step-by-step explanation:
multiple possibilities.
e.g.
we could use Pythagoras to get QR, and then use the law of sine to get angle P.
or we can use the law of sine to get angle R, and then use the rule that the sum of all angles in a triangle is always 180° to get angle P.
I propose the second option :
the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
with a, b, c being the sides always opposite of their associated angles.
33.8/sin(R) = 57.6/sin(90) = 57.6
sin(R) = 33.8/57.6 = 0.586805555...
R = 35.93064691...°
180 = 90 + 35.93064691... + P
P = 54.06935309...°
Answer:
x = -3 and x = -3/2
Step-by-step explanation:
After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:
p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>
p(x) = x^2(2x+3) <u>-9(2x+3)</u>
Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:
p(x) = (x^2 - 9)(2x+3)
Factor it once more because there's a difference of squares:
p(x) = (x+3)(x-3)(2x+3)
Now just plug in whatever makes the each bracket equal 0:
x = -3, x = 3, and x = -3/2
Those are your zeros.