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Alex17521 [72]
2 years ago
10

Plzzzzz someone help me

Mathematics
2 answers:
solong [7]2 years ago
4 0

The answer is The equation 3.5|6x – 2| = 3.5 has one solution


mixas84 [53]2 years ago
3 0

Answer:

The equation –0.3|3 + 8x| = 0.9 has no solution.

Step-by-step explanation:

The equation –3|2x + 1.2| = –1 has no solution.

|2x + 1.2| = 1/3

this should have 2 solutions


The equation 3.5|6x – 2| = 3.5 has one solution.

|6x – 2| = 1

this should have 2 solutions


The equation 5|–3.1x + 6.9| = –3.5 has two solutions.

|–3.1x + 6.9| = –3.5/5

this has no solutions  absolute values are positive


The equation –0.3|3 + 8x| = 0.9 has no solution.

|3 + 8x| = -0.9/.3

this should have no solutions since absolute values are positive

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Novay_Z [31]

Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

6 0
3 years ago
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Answer:

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7 0
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Answer:

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Add them together

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The total area is 300 ft^2

7 0
3 years ago
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