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Len [333]
11 months ago
8

40% of the students passed both exams. 80% of the students passed the second exam. how many students (in percent) who passed the

second exam also passed the first exam ? next
Mathematics
1 answer:
navik [9.2K]11 months ago
7 0

50%. students (in percent) who passed the second exam also passed the first exam.

Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.

Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.

Thus, both tests were passed by 40 of the 80 pupils who passed the second one:                                      

40/80 = 1/2 = 50%.

Find out more on Percentage at:

brainly.com/question/24877689

#SPJ4

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Answer:

a. 6  b. -2

Step-by-step explanation:

a. x^3 = 216

x = ³√216

x = 6

b. -n^3/4 = 2

-n^3 = 8

-n = ³√8

- n = 2

n = -2

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Step-by-step explanation:

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Thirty Mercedes and Audi participated in a 30 mile race. The average driving speed of the Mercedes and Audi were recorded. A ran
vladimir1956 [14]

Answer:

Median for sample 1 = 142

Median for sample 2 = 134

Step-by-step explanation:

For Sample 1:

For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.

120, 130, 132, 136, 139, 142, 142, 144, 156, 165, 167

The formula for calculating the term which will be median is:

Median= ((n+1)/2)

Here in sample 1, n=11

So, putting n=11 in the formula

= ((11+1)/2)

= (12/2)

=6th term

The sixth term is 142, so

Median of sample 1=142

For Sample 2:

For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.

112, 112, 113, 114, 125, 134, 141, 145, 146, 163, 165

The formula for calculating the term which will be median is:

Median= ((n+1)/2)

Here in sample 2, n=11

So, putting n=11 in the formula

=((11+1)/2)

=(12/2)

=6th term

The sixth term is 134, so

Median of sample 2=134

7 0
3 years ago
a share of stock in the bree medical supply company is quoted at 35 1/4. suppose you hold 20 shares of that stock, which you bou
erica [24]
Total number of stocks bought = 20
Rate at which each stocks were bought = 31 1/2
                                                             = 63/2
Rate at which 20 stocks were bought = 20 * (63/2) dollars
                                                             = 10 * 63 dollars
                                                             = 630 dollars
Rate at which each stocks were sold = 35 1/4
                                                             = 141/4 dollars
Rate at which 20 stocks were sold = 20 * (141/4) dollars
                                                         = 5 * 141 dollars
                                                         = 705 dollars
Then
Amount of profit made by selling 20 stocks = (705 - 630) dollars
                                                                      = 75 dollars
So the total amount of profit made is $75. The correct option in regards to the given question is option "D".
3 0
3 years ago
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