<span> The quadratic formula says that any quadratic equation of the form ax^2 + bx + c, then
x=(-b ± √(b^2 - 4ac))/2a, and so because of the square root, theres
obviously going to be no x-intercepts if b^2 - 4ac is negative, one
x-intercept if its zero, or two if its positive. So to calculate the
discriminant, which is whether it has an intercept, no intercepts or two
intercepts is:
∆=b^2 - 4ac, where delta, the greek equivalent of D, is used to represent the discriminant.
In the above equation a=-4, b=3 and c=-2, so
∆=3^2 - 4*-4*-2=9 - 32=-23, so because the discriminant is negative, then there are no x-intercepts.
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Answer:
shape I is similar to shape Il is a translation <u>6</u> right and <u>1</u> up, then a dilation by a scale factor of <u>1/2 (center:origin (0,0)</u>.
Step-by-step explanation:
shape I is similar to shape Il is a translation <u>6</u> right and <u>1</u> up, then a dilation by a scale factor of <u>1/2</u>.
we are given

To find solution , we can factor it and then we can solve for x
step-1: Factoring


step-2: Solve for x




so, option-C and option-F...........Answer
The first equation, 8x - 9y = - 23
Obtain the equation in slope- intercept form
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (
, 3) and (x₂, y₂ ) = (- 4, - 1 )
m =
= (- 4)/-
= 
partial equation is y =
x + c
to find c substitute either of the 2 points into the partial equation
using (- 4, - 1 ), then
- 1 = -
+ c ⇒ c = 
y =
x +
← in slope- intercept form
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
rearrange the slope- intercept equation into this form
multiply through by 9
9y = 8x + 23 ( subtract 9y and 23 from both sides )
8x - 9y = - 23 in standard form
First, we have
s1/r1 = s2/r2
The question also states the fact that
s/2πr = θ/360°
Rearranging the second equation, we have
s/r = 2πθ/360°
Then we substitute it to the first equation
s1/r1 = 2πθ1/360°
s2/r2 = 2πθ2/360°
which is now
2πθ1/360° = 2πθ2/360°
By equating both sides, 2π and 360° will be cancelled, therefore leaving
θ1 = θ2