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Len [333]
1 year ago
8

40% of the students passed both exams. 80% of the students passed the second exam. how many students (in percent) who passed the

second exam also passed the first exam ? next
Mathematics
1 answer:
navik [9.2K]1 year ago
7 0

50%. students (in percent) who passed the second exam also passed the first exam.

Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.

Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.

Thus, both tests were passed by 40 of the 80 pupils who passed the second one:                                      

40/80 = 1/2 = 50%.

Find out more on Percentage at:

brainly.com/question/24877689

#SPJ4

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The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they
Jobisdone [24]
The maximum profit is the y-coordinate of the vertex of the parabola represented by the equation.

P(c)=-20c^2+320c+5120 \\ \\
a=-20 \\
b=320 \\ \\
\hbox{the vertex } (h,k): \\
h=\frac{-b}{2a}=\frac{-320}{2 \times (-20)}=\frac{-320}{-40}=8 \\
k=f(h)=f(8)=-20 \times 8^2+320 \times 8+5120= \\
=-1280+2560+5120=6400

The maximum value is 6400, but the profit is given in hundreds of dollars, so multiply the value by 100.

The maximum profit the company can make is $640,000.
4 0
3 years ago
Read 2 more answers
The following graph represents the distance a commercial airplane travels over time, at cruising speed and an altitude of 35,000
ANEK [815]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

x ----> the time in hours

y ----> the distance in miles

<em>Find the value of k</em>

For the point (4,2268)

k=\frac{2,268}{4}=567\ mph

The slope represent the speed of the airplane

so

The linear equation is

y=567x

Part 1 :

The point (0,0) represents the starting point of the aircraft, when the time and distance are equal to zero. The cruising starts when time t = 0.

Part 2 :

The  point  (4, 2268) represents the plane after 4 hours of cruise , and shows it has traveled a distance of 2268 miles after 4 hours

3 0
3 years ago
3600 dollars is placed in an account with an annual interest rate of 9%. How much will be in the account after 25 years, to the
Mnenie [13.5K]
Assuming the interest is simple interest, as opposed to compound interest,

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3 0
2 years ago
Subtract.<br> (6x + 5) - (x+3)
Roman55 [17]

(6x+5)-(x+3).

6x+5-x-3.

Add the like terms.

6x-x+5-3.

We get.

5x+2.

6 0
2 years ago
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$1500 is invested at a rate of 3% compounded monthly. Write a compound interest function to model this situation. Then find the
Marianna [84]

Answer:

<u>Equation</u>:  F=1500(1.0025)^{12t}

<u>The balance after 5 years is:  $1742.43</u>

<u></u>

Step-by-step explanation:

This is a compound growth problem . THe formula is:

F=P(1+\frac{r}{n})^{nt}

Where

F is future amount

P is present amount

r is rate of interest, annually

n is the number of compounding per year

t is the time in years

Given:

P = 1500

r = 0.03

n = 12 (compounded monthly means 12 times a year)

The compound interest formula modelled by the variables is:

F=1500(1+\frac{0.03}{12})^{12t}\\F=1500(1.0025)^{12t}

Now, we want balance after 5 years, so t = 5, substituting, we get:

F=1500(1.0025)^{12t}\\F=1500(1.0025)^{12*5}\\F=1500(1.0025)^{60}\\F=1742.43

<u>The balance after 5 years is:  $1742.43</u>

3 0
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