Answer:
check the illustration I provided
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
because I am smart and cause im smart
Answer:
The domain of the function (cd)(x) will be all real values of x except x = 2.
Step-by-step explanation:
The two functions are
and d(x) = x + 3
So, (cd)(x) = ![(\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}](https://tex.z-dn.net/?f=%28%5Cfrac%7B5%7D%7Bx%20-%202%7D%29%28x%20%2B%203%29%20%3D%20%5Cfrac%7B5%28x%20%2B%203%29%7D%7Bx%20-%202%7D)
Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.
Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)
Answer:
3
Step-by-step explanation: