Answer:
The first error that Tomas made was added 6 to both sides of the equation instead of subtracting 6
Step-by-step explanation:
Let
x ----> represents the number of pounds of granola
y ----> represents the number of pounds of walnuts
we know that
The linear equation that represent this scenario is
2x+6y=12 -----> equation A
x=3 -----> equation B
substitute equation B in equation A and solve for y
2(3)+6y=12
6+6y=12
Subtract 6 both sides
6+6y-6=12-6
6y=6
Divide by 6 both sides
6y/6=6/6
y=1
so
The number of pounds of walnuts is 1
therefore
The first error that Tomas made was added 6 to both sides of the equation instead of subtracting 6
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value = 
= 5.29
Answer:
Step-by-step explanation:
Eliminating a negative and changing our operation
Rewriting our equation with parts separated
Solving the whole number parts
Solving the fraction parts
![-\frac{5}{6} +\frac{1}{4} =[?]](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B4%7D%20%3D%5B%3F%5D)
Find the LCD of 5/6 and 1/4 and rewrite to solve with the equivalent fractions.
LCD = 12
Combining the whole and fraction parts
[RevyBreeze]
Solve for r using factoring:
Solve for r:
r^2 - 8 r - 33 = 0
The left hand side factors into a product with two terms:
(r - 11) (r + 3) = 0
Split into two equations:
r - 11 = 0 or r + 3 = 0
Add 11 to both sides:
r = 11 or r + 3 = 0
Subtract 3 from both sides:
Answer: r = 11 or r = -3
