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choli [55]
3 years ago
6

what is the greatest six digit number in which the thousands place is twice the digit in the tens place what is the least number

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0
998994 and 112111
This seems to be the best numbers
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Multiply the following binomials.<br> (4x-6)(x-7)
Alexxandr [17]

Answer:

4x^2 -34x+42

Step-by-step explanation:

(4x-6)(x-7)

FOIL

first 4x*x = 4x^2

outer 4x*-7 = -28x

inner : -6 *x = -6x

last : -7*-6 = 42

Add them together = 4x^2 -28x-6x +42

                                =4x^2 -34x+42

7 0
3 years ago
could you possibly help me with this question? (its not part of a graded assignment, just a review from an online course of mine
Virty [35]

Let:

x = Pounds of walnuts in the mix.

Each pound of walnuts costs $0.80. thus x pounds of walnuts cost 0.8x dollars.

Each pound of cashews costs $1.25 and the mix will contain 8 pounds of cashews, so the cost is 8*$1.25 = $10

The total cost of the mix is, therefore: 0.8x + 10 dollars.

We are also given the pound of mix costs $1.00 and we have a total of 8 + x pounds, so the total cost of the mix is 1*(8 + x) dollars.

Equating both costs:

0.8x + 10 = 1*(8 + x)

Operating:

0.8x + 10 = 8 + x

Subtracting x and 10:

0.8x - x = 8 - 10

Simplifying:

-0.2x = -2

Dividing by -0.2:

x = -2/(-0.2)

x = 10

Answer: 10 pounds

8 0
1 year ago
Match each function with the correct translation of the parent function f(x) = |x|
GarryVolchara [31]

Answer:they are all straight across so drag each line to the one that is across from the equation

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve the following equation.
miskamm [114]
Can you post the rest of the question please?
3 0
3 years ago
Read 2 more answers
A right triangle has one vertex on the graph of y = 9 - x^2 , x &gt; 0, at ( x , y ), another at the origin, and the third on th
jenyasd209 [6]

Answer:

  a.  A(x) = (1/2)x(9 -x^2)

  b.  x > 0 . . . or . . . 0 < x < 3 (see below)

  c.  A(2) = 5

  d.  x = √3; A(√3) = 3√3

Step-by-step explanation:

a. The area is computed in the usual way, as half the product of the base and height of the triangle. Here, the base is x, and the height is y, so the area is ...

  A(x) = (1/2)(x)(y)

  A(x) = (1/2)(x)(9-x^2)

__

b. The problem statement defines two of the triangle vertices only for x > 0. However, we note that for x > 3, the y-coordinate of one of the vertices is negative. Straightforward application of the area formula in Part A will result in negative areas for x > 3, so a reasonable domain might be (0, 3).

On the other hand, the geometrical concept of a line segment and of a triangle does not admit negative line lengths. Hence the area for a triangle with its vertex below the x-axis (green in the figure) will also be considered to be positive. In that event, the domain of A(x) = (1/2)(x)|9 -x^2| will be (0, ∞).

__

c. A(2) = (1/2)(2)(9 -2^2) = 5

The area is 5 when x=2.

__

d. On the interval (0, 3), the value of x that maximizes area is x=√3. If we consider the domain to be all positive real numbers, then there is no maximum area (blue dashed curve on the graph).

5 0
3 years ago
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