Answer:
4x^2 -34x+42
Step-by-step explanation:
(4x-6)(x-7)
FOIL
first 4x*x = 4x^2
outer 4x*-7 = -28x
inner : -6 *x = -6x
last : -7*-6 = 42
Add them together = 4x^2 -28x-6x +42
=4x^2 -34x+42
Let:
x = Pounds of walnuts in the mix.
Each pound of walnuts costs $0.80. thus x pounds of walnuts cost 0.8x dollars.
Each pound of cashews costs $1.25 and the mix will contain 8 pounds of cashews, so the cost is 8*$1.25 = $10
The total cost of the mix is, therefore: 0.8x + 10 dollars.
We are also given the pound of mix costs $1.00 and we have a total of 8 + x pounds, so the total cost of the mix is 1*(8 + x) dollars.
Equating both costs:
0.8x + 10 = 1*(8 + x)
Operating:
0.8x + 10 = 8 + x
Subtracting x and 10:
0.8x - x = 8 - 10
Simplifying:
-0.2x = -2
Dividing by -0.2:
x = -2/(-0.2)
x = 10
Answer: 10 pounds
Answer:they are all straight across so drag each line to the one that is across from the equation
Step-by-step explanation:
Can you post the rest of the question please?
Answer:
a. A(x) = (1/2)x(9 -x^2)
b. x > 0 . . . or . . . 0 < x < 3 (see below)
c. A(2) = 5
d. x = √3; A(√3) = 3√3
Step-by-step explanation:
a. The area is computed in the usual way, as half the product of the base and height of the triangle. Here, the base is x, and the height is y, so the area is ...
A(x) = (1/2)(x)(y)
A(x) = (1/2)(x)(9-x^2)
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b. The problem statement defines two of the triangle vertices only for x > 0. However, we note that for x > 3, the y-coordinate of one of the vertices is negative. Straightforward application of the area formula in Part A will result in negative areas for x > 3, so a reasonable domain might be (0, 3).
On the other hand, the geometrical concept of a line segment and of a triangle does not admit negative line lengths. Hence the area for a triangle with its vertex below the x-axis (green in the figure) will also be considered to be positive. In that event, the domain of A(x) = (1/2)(x)|9 -x^2| will be (0, ∞).
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c. A(2) = (1/2)(2)(9 -2^2) = 5
The area is 5 when x=2.
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d. On the interval (0, 3), the value of x that maximizes area is x=√3. If we consider the domain to be all positive real numbers, then there is no maximum area (blue dashed curve on the graph).