All categories

3 years ago

Find the number of positive divisors of 1470.

Mathematics

2 answers:

julsineya [31]3 years ago

6 0

Answer:

1, 3, 17, 29, 51, 87, 493, 1479

Step-by-step explanation:

Divisors of number 1479: 1, 3, 17, 29, 51, 87, 493, 1479

Number of divisors: 8

Sum of its divisors: 2160

Alecsey [184]3 years ago

4 0

Answer: plz mark as brainliest

Step-by-step explanation:Here we will define what "the divisors of 1470" means and show you how to find the divisors of 1470.

First, note that in a division problem like x divided by y equals z, x is the dividend, y is the divisor, and z is the quotient as illustrated here:

Dividend / Divisor = Quotient

Divisors of 1470 are all the unique whole number divisors that make the quotient a whole number if you make the dividend 1470:

1470 / Divisor = Quotient

To find all the divisors of 1470, we first divide 1470 by every whole number up to 1470 like so:

1470 / 1 = 1470

1470 / 2 = 735

1470 / 3 = 490

1470 / 4 = 367.5

etc...

Then, we take the divisors from the list above if the quotient was a whole number. This new list is the Divisors of 1470.

The Divisors of 1470 are as follows:

1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 49, 70, 98, 105, 147, 210, 245, 294, 490, 735, and 1470.

You might be interested in

Plot the intercepts to graph the equation. x+y=3

andrey2020 [161]

Answer: You will have points plotted at +3 on the y axis, and +3 on the x axis.

The attachment shows what your graph should look like.

Step-by-step explanation:

The intercept is where the graphed line crosses an axis.

To find the y-intercept, substitute 0 for x and solve for y:

0 + y = 3. Subtracting 0, you have y = 3

So you can plot a point at +3 on the y axis.

To find the x- intercept, substitute 0 for y, and solve for x

x + 0 = 3 Again, subtracting 0, x = 3

So plot a point on the x-axis at +3

Use the line tool to connect the two points.

5 0

3 years ago

What is the inverse of the function f(x) = 2x + 1?|

padilas [110]

Answer:

1st option

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = 2x + 1 ( subtract 1 from both sides )

y - 1 = 2x ( divide both sides by 2 )

$\frac{y-1}{2}$ = x

Change y back into terms of x with x being the inverse h(x)

h(x) = $\frac{x-1}{2}$ = $\frac{1}{2}$ x - $\frac{1}{2}$

6 0

2 years ago

Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"

Levart [38]

Answer:

$\huge\boxed{f(-1) = -7}$

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

$f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3$

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

$3(-1)^4 = 3$

WAIT! How is this possible? $-1^4 = -1$ (according to my calculator), and $3 \cdot -1 = -3$ , not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use $-2^2$ as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than being "-2 squared" - it's "the negative of of 2 squared."

Tying this back into our problem, the squared method would only be true if it looks like $-1^4$ . However, since we're substituting in -1, it looks like $(-1)^4$ , so the expression reads out as "-1 to the fourth."