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Anika [276]
3 years ago
9

Can you determine the solution of the |4x−2|≥−6 without solving?

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

|4x-2|">"-6

add 2 to both sides

4x">"-4

divide both sides by 4

x">"-1

the ">" means greater than or equal to, I just don't have that character on my keyboard

Step-by-step explanation:

so the answer is x is greater than or equal to -1

IN: (-∞,-1]

for number line: You would write the number line from -1-10  

then, you would put  a closed dot on negative one, with an arrow going to the right!

Hope this helped! <3

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For which scatterplot is the correlation strongest ?
PtichkaEL [24]

the second one? Step-by-step explanation:

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3 years ago
Aline crosses the coordinates (-4,4) and (2.-5). What is the slope<br> of the line?
lisabon 2012 [21]

Answer:

Step-by-step explanation:

Use the slope formula:

m = \frac{y2 -y1}{x2 - x1}

where m = slope

Given the coordinates

(-4, 4) ---> this means x1 = -4 , y1 = 4

(2, -5) ---> this means x2 = 2 , y2 = -5

Substitute these values into the slope formula:

m = \frac{y2 -y1}{x2 - x1}

m = \frac{-5 -4}{2 - (-4)}  = \frac{-9}{2+4} = \frac{-9}{6} = \frac{-3}{2}

4 0
3 years ago
What is the output of the following Python program? list1 = [2, 3, 4] list2 = [1, 5] list3 = [0] list3 = list2 + list1 print(lis
Sphinxa [80]

Answer: the answer is b

Step-by-step explanation:

from the initial list 3 is contain 0 that is [0]

but now list has been updated to list 2+ list 1, so the elements contains in list 3 will be list 2 plus list 1

[1,5,2,3,4]

8 0
3 years ago
A circle has a diameter of 26 units. What is the area of the circle to the nearest hundredth of a square unit.
iris [78.8K]

9514 1404 393

Answer:

  530.93 square units

Step-by-step explanation:

The area of a circle in terms of diameter can be found by ...

  A = (π/4)d²

  A = 3.14159/4×26² ≈ 530.929

Rounded to hundredths, the area of the circle is 530.93 square units.

7 0
3 years ago
Find the perimeter of A(-3,2), B(6,6), and C(7,-1).<br><br>Please show work.
Furkat [3]

AB=√{(6+3)²+(6-2)^2}=√(81+16)=√(97)

BC=√((7-6)²+(-1-6)²)=√(50)=5√2

AC=√((7+3)²+(-1-1)²)=2√(26)

Perimeter=AB+BC+AC=√97+5√2+2√(26)

3 0
3 years ago
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