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REY [17]
3 years ago
13

What is the mean of these set of numbers {–8, –4, –3, –11}?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0
I think the correct answer among the choices listed above is option A. Mean is synonymous to the average of the set of numbers. It is calculated by adding up the numbers divided by the number of data added.

Mean = (-8 + -4 + -3 + -11) / 4 = -6.5
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garri49 [273]
5 · 5 - 4 · 4 = 9 sorry if I'm wrong
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5 0
3 years ago
In a survey of 12 people, it was found that an average of $36 was spent on their child's last birthday gift with a standard devi
Nataliya [291]

Answer:

(27.3692 ; 44.6308)

Step-by-step explanation:

Mean, xbar = 36

Standard deviation, s = 11

Sample size, n = 12

Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718

Confidence interval :

Xbar ± Margin of error

Margin of Error = Tcritical * s/sqrt(n)

Margin of Error = 2.718 * 11/sqrt(12) = 8.6308

Confidence interval :

Lower boundary : 36 - 8.6308 = 27.3692

Upper boundary : 36 + 8.6308 = 44.6308

(27.3692 ; 44.6308)

3 0
3 years ago
Monique made several batches of soup for a potluck supper. Each batch required 3/4 of a pound of potatoes, and she used a total
Rina8888 [55]

Answer:

B and E

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The augmented matrix of a consistent system of five equa- tions in seven unknowns has rank equal to three. How many parameters a
dangina [55]

Answer:

It is necessary four parameters.

Step-by-step explanation:

Since the augmented matrix of the consistent system has rank equal to three then the number of free variables is (number of unknows)-rank then there are 7-3=4 free variables. This means that are necessary four parameter to specify all solutions.

5 0
3 years ago
In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

\overline{RN}=\overline{QN}

By Pythagorean theorem, for triangle NQP:

\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}

Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

3 0
3 years ago
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