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3 years ago

13

A person bought a water tank of circular base having the radius 1.05 meter and height 3.5 meter for the use of own house from th

e shop. If the upper part of the tank is semi
spherical, how many liters of water will be contained in the
tank? Find it.

1 answer:

Anastasy [175]3 years ago

8 0

Answer:

I am not very sure is my answer correct or not, sorry

Hope that I can help you

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The Roman numeral which represents the number in standard form for 3,089 is?

Tresset [83]

MMMLXXXIX

~ hope this helps!

4 0

2 years ago

Latoya has b decks of cards . Each deck has 52 cards in it , what is the expression for the total numbers of cards latoya has

Lerok [7]

Answer:

52b

Step-by-step explanation:

She has 52 cards per deck, and b decks.

This means she has 52b cards.

How this works:

For 1 deck, she has 52 cards, or 52×1 cards.

For 2 decks, she has 104 cards, or 52×1 cards.

For 5 decks, she has 260 cards, or 52×5 cards.

For 10 decks, she has 520 cards, or 52×10 cards.

Therefore, for b decks, she has 52×b, or 52b cards.

**This content involves writing algebraic expressions, which you may wish to revise. I'm always happy to help!

6 0

3 years ago

46.The function f graphed above is the function f(x) = log2(x) + 2 for x > 0. Find a formula for the inverse of this function

pantera1 [17]

Answer:

The inverse for log₂(x) + 2 is - log₂x + 2.

Step-by-step explanation:

Given that

f(x) = log₂(x) + 2

Now to find the inverse of any function we put we replace x by 1/x.

f(x) = log₂(x) + 2

f(1/x) =g(x)= log₂(1/x) + 2

As we know that

log₂(a/b) = log₂a - log₂b

g(x) = log₂1 - log₂x + 2

We know that log₂1 = 0

g(x) = 0 - log₂x + 2

g(x) = - log₂x + 2

So the inverse for log₂(x) + 2 is - log₂x + 2.

3 0

3 years ago

Anni [7]

Answer:

a) = 4.5

b) = 3.3

Step-by-step explanation:

Before solving our problems given to us let us under stand the rule of cube roots

It says $\sqrt[3]{x \times x \times x} = x$ -----(A)

Also

$\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y$ ---(B)

Now let us see each part one by one

a) we have

$\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}$

Now 64 = 4 x 4 x 4

0.027 = 0.3 x 0.3 x 0.3

0.008 = 0.2 x 0.2 x 0.2

substituting these values

$\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}$

Applying Rule A in above

$=4+0.3+0.2$

$=4+0.5$

4.5

b) we have $\sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}$

Applying the B rule in this

$=0.3 \times 11$

3.3

4 0

3 years ago

Solve for y. <br> 2x+6y=12

Veronika [31]

2x + 6y = 12

2x - 2x + 6y = 12 - 2x

6y = 12 - 2x

6y/6 = 12/6 - 2x/6

Y = 2 - 2/6 X

Y = 2 - 1/3 X or

Y = -1/3 X + 2.

7 0

3 years ago