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laila [671]
3 years ago
8

The Knicks and Nets have a total 30 players.

Mathematics
1 answer:
Blababa [14]3 years ago
5 0

Answer:

Step-by-step explanation:

From the problem statement, we can set up the following two equations:

K + N = 30

20K + 10N = 500

where K is the number of Knicks players, and N is the number of Nets players.

We can substitute the first equation into the second and solve for K

K + N = 30

N = 30 - K

20K + 10N = 500

20K + 10(30 - K) = 500

20K + 300 - 10K = 500

10K + 300 = 500

10K = 200

K = 20

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Answer:

B and D

Step-by-step explanation:

10x^2 -vx [ has the highest power of X as 2 , so it is to degree 2].

6x^2 - 6x + 5[ has the highest power of x as 2; hence it is to degree 2]

4 0
3 years ago
2x – 4y = 14<br> x = 2y – 2<br><br> What is the solution to the system?
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2x-4y=14
X=2y-2

2x-4y=14
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x-2y=12
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Daisies first summer job was working behind the counter at Dairy Queen he earned double time for any hours worked over 40 in a g
FrozenT [24]

Answer: the standard hourly pay is $3.05

Step-by-step explanation:

Let x represent the standard hourly pay that he gets for the first 40 hours.

Therefore, the total amount that he gets for the first 40 hours of work in a given week is 40x.

At Dairy Queen, he earned double time for any hours worked over 40 in a given week. This means that the hourly rate is 2x

If during one week, he worked 51 hours, it means that the overtime is 51 - 40 = 11 hours

Total amount earned for overtime is

11 × 2x = 22x

If the total amount that he earned for the week is $189.10, then

40x + 22x = 189.1

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8 0
4 years ago
which of the three sets could not be the lengths of the sides of a triangle {6,10,12} {5,7,10} {4,4,9} {2,3,3}
Phoenix [80]

So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

A+B>C\\A+C>B\\B+C>A

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

2+3>3\\5>3\ \textsf{true}\\\\2+3>3\\5>3\ \textsf{true}\\\\3+3>2\\6>2\ \textsf{true}

<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

5 0
3 years ago
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Here is the result.....

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