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Elza [17]
2 years ago
14

Evaluate the expression when y=-3

Mathematics
2 answers:
Ratling [72]2 years ago
7 0
Y=-3
subtitute to y^2 + 6y +8
= (-3)^2 + 6(-3) + 8
= 9-18+8
= -1
valkas [14]2 years ago
5 0

Answer:

-1

Step-by-step explanation:

Substitute in the known variables:

y^2 + 6y + 8\\(-3)^2 + 6(-3) + 8\\

-3 * -3 = 9\\(-3)^2 = 9

9 + 6(-3) + 8\\9 + (-18) + 8\\9 - 18 + 8

= -1

Hope this helps!

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Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

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The nonzero vector orthogonal to the plane through the points P,Q, and R is

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\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

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