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Ludmilka [50]
3 years ago
7

Can someone please answer this question please answer it quickly I need it please answer it correctly and please please show wor

k

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

2.5×2 + 2.5×4 + 2.5×3

Take 2.5 common

2.5(2 + 4 + 3)

motikmotik3 years ago
3 0

Answer:

The answer is B

Step-by-step explanation:

1. 2.50 x 2 is $5

2. 2.50 x 4 is $10

3. 2.50 x 3 is $7.50

4. 5 + 10 + 7.50 is 22.50 so you know the total should be 22.50.

5. It cant be A because 2.50 x 2 is 5 then timesing that by four would make 20 and then by 3 that would make $60 not $22.50

6. It is B because 2 + 4 + 3 is 9, 9x2.50 is 22.50

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5. a) Which figure is the mapping diagram of the relation
Viefleur [7K]

Answer:

b, since the others have the input and output on the wrong sides

7 0
3 years ago
Read 2 more answers
Write and solve an equation for each problem situation. Define the variable
Simora [160]

Answer:

His weekly allowance is $5.50.

Step-by-step explanation:

12.03 - 6.53 = $5.50

I'm not 100% sure this is accurate. Good Luck!

8 0
2 years ago
Need help with this question
Ne4ueva [31]

Answer:

About 3%

Step-by-step explanation:

It decreased.

3% of 465056=13951

465056-13951=451105

3.6% of 465056=16742

465056-16742=448314

The amount you want it 450678 and 451105 is closer to 450678 than 448314.

4 0
2 years ago
There is a bag with only red marbles and blue marbles.
9966 [12]

Answer:

There are 60 marbles in the bag

Step-by-step explanation:

The total number of marbles  times the probability of red marbles = number of red marbles

total * 7/10 = 42

Multiply each side by 10/7

total * 7/10 * 10/7 = 42*10/7

total

60

There are 60 marbles in the bag

7 0
3 years ago
An airline has a policy of booking as many as 150 persons on a plane that seats 140. past studies indicate that only 85% of book
RUDIKE [14]
Binomial distribution will be used to model situation because all following criteria are satisfied:
1. Bernoulli trials, i.e. exactly two possible outcomes (show up or not)2. Number of trials is known before and constant throughout the experiment, i.e. independent of outcomes (150 booked)3. All trials are independent of each other. (assumed from context)4. Probability of success is known, and remain constant throughout trials. (85%)Since all criteria are satisfied, we can model with binomial distribution, where the probability of x successes out of N trials each with probability of success p is given byP(x)=C(N,x)(p^x)(1-p)^(N-x)and,C(N,x) is number of combinations of selecting x objects out of N.
P(>140)=P(141)+P(142)+...+P(150)
=.00035620+0.00012783+0.00004056+0.00001117+0.00000262+0.00000051+0.00000008+0.00000001+0.00000000
=0.00053907

The above calculation is not very practical unless we have a statistical calculator or a software.

For practical hand calculations, we usually use the binomial approximation.
mean=np=150*0.85=127.5
variance = np(1-p)=150*.85*.15=19.125  (>10, possible to use binomial approximation, but accuracy is marginal).
We also need to use the continuity correction, which means that the portion above 140 is counted as 140.5 to 150 passengers.  Then we calculate
Z=(140.5-127.5)/sqrt(19.125)=2.973
P(x>=140.5)
=P(z>=Z)
=1-P(z<Z)
=1-P(z<2.973)
=1-0.99852
=0.00148
The answer is quite a bit off from the exact value of 0.000539, but an approximation is an approximation especially for skew distribution like in the present case (p=0.85 far from 0.5, and x=140 far from mean).
3 0
3 years ago
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