3. Vlad (the vampire) wanted to line the inside of his cofin bed with purple cloth. He measured

7nadin3 [17]

She needs 1/6 almonds , 1/3 walnuts and 1/2 of raisins as a fraction of total trail mix.
So she spends $2.5 on almonds. $5 on walnuts and $10 on raisins (total $15)

so that is 2.5/12 = 0.208 pounds almonds
5 / 10.5 = 0.476 pound walnuts
10/4 = 2.5 pounds raisins

so total wieght of the trail mix is 3.19 pounds

8 0

3 years ago

List at least three example of racial injustice that king uses as effective support for his claim that African American are not

Effectus [21]

The following are the list of the racial injustice that king uses as effective support for his claim that african american are not free.
#1. He uses word to contrast the racial situation in the country in the past and present to what is expected in the future,
#2 The king shows that there is hope for change in the future
#3. The king uses metaphor.

6 0

3 years ago

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

3 years ago

Maria has 14 pencils, Ted has 9 pencils, Tom has 12, pencils, Lucinda has 13 pencils, so that they all have the same amount? How

Nina [5.8K]

Answer:

I say 12, but i can be wrong.

Step-by-step explanation:

6 0

3 years ago

Please answer this question :)

sveticcg [70]

Answer:

a) 49.41

b) not quite sure

Step-by-step explanation:

sorry

6 0

3 years ago