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Flauer [41]
3 years ago
15

Linda needs to come up with a 10 percent down payment on a house priced at $127,400.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0

Answer:

$12,740

Step-by-step explanation:

127,400 x .10 = 12,740

10% = 0.10

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Lemur [1.5K]
To simply the expression,we should remember an ! in math represents every number (til 1) before that one multiplied or "the product of the integers from 1 to n"

So now that we have the definitions we can simplify by finding the values of each:

(9x8x7x6x5x4x3x2x1)-(4x3x2x1)(5x4x3x2x1)

After simplifying this will equal to 3600

6 0
3 years ago
This is due next period. I need answers and a small explanation/work.
vlada-n [284]

1) Cancel out the common factor which in this case is 8 \frac{16m^2}{24m^7} = \frac{2m^2}{3m^7}

2)First apply exponent rule \frac{n(n+7)}{4n(n+7)}\\ now cancel out the common factors which are n and n+7 leaving you with \frac{1}{4}=0.25

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5) In the picture

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6 0
3 years ago
The number of fiction books in a libary is %150 of the number of non-fiction books. the libary has 4,000 books in total. how man
Nitella [24]

Answer:

The number of

Fiction books = x = 2400 fiction books

Non fiction books = y = non fiction books

Step-by-step explanation:

Let the number of

Fiction books = x

Non fiction books = y

The libary has 4,000 books in total.

Hence: x + y = 4000........ Equation 1

The number of fiction books in a libary is %150 of the number of non-fiction books.

x = 150% of y

x = 150/100 × y

x = 1.5y

We substitute 1.5y for x in Equation 1

x + y = 4000

1.5y + y = 4000

2.5y = 4000

y = 4000/2.5

y = 1600 non fiction books

Solving for x

x = 1.5y

x = 1.5 × 1600

x = 2400 fiction books.

Therefore,

The number of

Fiction books = x = 2400 fiction books

Non fiction books = y = non fiction books

5 0
3 years ago
Does anybody know the answer's to, 2,3, and 4?
Jobisdone [24]
2, No solution
3, Infinite many solutions
4, (0,-3)
i hope i was able to help!! so sorry if i made a mistake
7 0
2 years ago
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
3 years ago
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