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devlian [24]
4 years ago
9

Electrical engineers find it convenient to model impedance with complex numbers. In a parallel AC circuit with two impedances 21

and 22, the equivalent or total impedance in ohms can be determined by using the Z₂ Z2 formula Zeg Find the equivalent impedance Zeg for 21 = 2-i and 21-22 22 = 1 + i arranged in a parallel AC circuit. The equivalent impedance in a parallel AC circuit is Zeq = i.​
Mathematics
1 answer:
BARSIC [14]4 years ago
3 0
Idk points points points
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Sellus
igor_vitrenko [27]

Answer:

3.9

Step-by-step explanation:

Given the data:

Payout ($) (x) : 0 2 4 8 10

Probability p(x) : 0.35 0.2 0.1 0.2 0.15

The expected winning ; E(X) = Σ(x * p(x))

Σ(x * p(x)) = (0*0.35)+(2*0.2)+(4*0.1)+(8*0.2)+(10*0.15)

= 0 + 0.4 + 0.4 + 1.6 + 1.5

= 3.9

8 0
3 years ago
Find the Solution of the system of equations.<br><br> -4x+3y=-21<br> -2x-3y=3
LUCKY_DIMON [66]

Answer:

(3, - 3)

Step-by-step explanation: that might be it

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3 years ago
2 yd<br> 3.1 yd <br> find the area
STALIN [3.7K]

Answer:

Area = 6.2 yards²

Step-by-step explanation:

area = bh

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Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb
miv72 [106K]

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Step-by-step explanation:

5 0
4 years ago
Please try your best and show your work and I will give brainliest!
dimulka [17.4K]

Answer:

Part A: impossible

Part B: Either equal or blue

Part C: 9 green and 2 blue were added

Step-by-step explanation:

Part A:

The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.

Part B:

I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.

Part C:

The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.

I hope this helps and please mark me as brainliest!

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2 years ago
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