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Virty [35]
3 years ago
6

Find the Solution of the system of equations. -4x+3y=-21 -2x-3y=3

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

(3, - 3)

Step-by-step explanation: that might be it

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Solve for x...........................
yaroslaw [1]

Answer:

Option A is correct, i.e. x = -3, x = 7.

Step-by-step explanation:

Given the equation is x² -4x -21 = 0.

We can compare it with general quadratic equation i.e. ax² +bx +c =0.

then a = 1, b = -4, c = -21.

We can use Quadratic formula as follows:-

x = ( -b ± √(b²-4ac) )/2a

x = ( +4 ± √(16-4*1*-21) )/2*1

x = ( +4 ± √(16+84) )/2

x = ( +4 ± √(100) )/2

x = ( +4 ± 10 )/2

x = (4+10)/2 or x = (4-10)/2

x = 14/2 or x = -6/2

x = 7 or x = -3

Hence, option A is correct, i.e. x = -3, x = 7.

5 0
3 years ago
Please help me wit dis rq
Sonja [21]
I think is you just need to multiply that input number just to get the right answers
Example: 5 multiply by 5 equal 25
Try it
7 0
2 years ago
Read 2 more answers
What is the answer pls explain​
natita [175]

Answer:

no pic?

Step-by-step explanation:

4 0
3 years ago
A photographer’s camera sits on a tripod that is 1.8 m above the ground. The base of the tripod is 44 m from the base of a tree.
ryzh [129]
I found 37.4 m.
I tried using trigonometry and the tangent of an angle (in this case 39°):


6 0
3 years ago
Find the rectangular coordinates of the point. (-5, -180°)
o-na [289]
\bf \begin{array}{rlclll}
(-5&,&-180^o)\\
\uparrow &&\uparrow \\
r&&\theta 
\end{array}\quad 
\begin{cases}
x=rcos(\theta )\\
\qquad -5\cdot cos(-180^o)\\
\qquad -5\cdot -1\\
\qquad 5\\
----------\\
y=rsin(\theta )\\
\qquad -5\cdot sin(-180^o)\\
\qquad -5\cdot 0\\
\qquad 0
\end{cases}\implies (5,0)
4 0
3 years ago
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