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Virty [35]
3 years ago
6

Find the Solution of the system of equations. -4x+3y=-21 -2x-3y=3

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

(3, - 3)

Step-by-step explanation: that might be it

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I NEED HELP W THIS QUESTION!!
Kobotan [32]

Answer:

A

Step-by-step explanation:

To find the value you can just find 12% of each number (trial and error), until one of them gives you 90 as an answer:

A) 750

750 *  0.12 = 90

B) 1080

1080 * 0.12 = 129.6

C) 360

360 * 0.12 = 43.2

D) 1168

1168 * 0.12 = 140.16

This tells you that 90 is 12% of the 750, and that is why it is your answer


I hope this helps!

8 0
3 years ago
Please help i need help
DaniilM [7]

Answer:

what is this

Step-by-step explanation:

7 0
3 years ago
Ben is taking a typing class, and the following line graph represents the number of words per minute he was able to type each we
Crank
During week 2, he could type 15 words per minute, at his fourth week, he could type 30. So 30-15=15. He could type 15 words faster on week 4 than he could at week 2.
3 0
4 years ago
3х – 8y = 19<br> 3х + 5y = — 46
Vadim26 [7]

Answer:

-5

Step-by-step explanation:

multiple the second equation by negative then subtract or add the equations and the answer will be negative 5

4 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}&#10;\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}&#10;\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}&#10;\\&#10;\\ \text{z-score} = \frac{720 - 600}{100}&#10;\\&#10;\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) &#10;\\ = P(z \ \textgreater \  1.2)&#10;\\ = 1 - P(z \leq 1.2)&#10;\\ = 1 - 0.885&#10;\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
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