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zavuch27 [327]
3 years ago
13

Help plz!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
lukranit [14]3 years ago
8 0

Answer:

6

Step-by-step explanation:

lower quarter is 10

higher quarter is 16

16-10=6

Elena-2011 [213]3 years ago
8 0

Answer:

Step-by-step explanation:

The answer is six. The lq is 10 and the Hq is 16. 16-10=6

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A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. If 110 pounds of beans create a mixture that
garik1379 [7]

Answer:

B = 87.08 pounds @ $0.32

A = 22.92 pounds @ $0.08

Step-by-step explanation:

given,

cost of beans (A)= $ 0.08/pound

and another beans cost (B) = $ 0.32 /pound

total weight of the pound = 110 pound

selling price of mixture = $ 0.27/pound

cost of each bean = ?                    

A + B = 110                                

A = 110 - B-------(1)                        

0.08 A + 0.32 B = 0.27 x 110

0.08 A + 0.32 B = 29.7                

Putting value of A                    

0.08(110 - B) + 0.32 B = 29.7

8.8 - 0.08 B + 0.32 B = 29.7

0.24 B = 20.9

B = 87.08 pounds @ $0.32

A = 22.92 pounds @ $0.08

8 0
3 years ago
Factor 10x2<br> + 11x + 3
wlad13 [49]

Answer:

e

Step-by-step explanation:

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5 0
2 years ago
Show that h= r(csc(theta)-1)
Alex

Answer:

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5 0
2 years ago
An airplane heading due east has a velocity of 210 miles per hour. A wind is blowing from the north at 38 miles per hour. What i
Nimfa-mama [501]

Answer:

The resultant velocity of the airplane is 213.41 m/s.

Step-by-step explanation:

Given that,

Velocity of an airplane in east direction, v_1=210\ mph

Velocity of wind from the north, v_2=38\ mph

Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.

We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :

v=\sqrt{v_1^2+v_2^2}

v=\sqrt{(210)^2+(38)^2}

v = 213.41 m/s

So, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.

4 0
2 years ago
Please help, super hard question for me!
dem82 [27]

Answer:

Step-by-step explanation:

When using the substitution method we use the fact that if two expressions y and x are of equal value x=y, then x may replace y or vice versa in another expression without changing the value of the expression.

Solve the systems of equations using the substitution method

{y=2x+4

{y=3x+2

We substitute the y in the top equation with the expression for the second equation:

2x+4            =      3x+2

4−2              =        3x−2

2===             =         x

To determine the y-value, we may proceed by inserting our x-value in any of the equations. We select the first equation:

y= 2x + 4

We plug in x=2 and get

y=  2⋅2+4 = 8

The elimination method requires us to add or subtract the equations in order to eliminate either x or y, often one may not proceed with the addition directly without first multiplying either the first or second equation by some value.

Example:

2x−2y = 8

x+y = 1

We now wish to add the two equations but it will not result in either x or y being eliminated. Therefore we must multiply the second equation by 2 on both sides and get:

2x−2y = 8

2x+2y = 2

Now we attempt to add our system of equations. We commence with the x-terms on the left, and the y-terms thereafter and finally with the numbers on the right side:

(2x+2x)  + (−2y+2y) =  8+2

The y-terms have now been eliminated and we now have an equation with only one variable:

4x = 10

x= 10/4 =2.5

Thereafter, in order to determine the y-value we insert x=2.5 in one of the equations. We select the first:

2⋅2.5−2y     =  8

5−8             = 2y

−3               =2y

−3/2            =y

y                 =-1.5

6 0
2 years ago
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