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juin [17]
3 years ago
13

Has anyone taken the PERT? If so, what was it like? What was the math part like?

Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

guessed through it and made a 100 out of 150 pretty easy dude ( i'm only 14 so you can imagine how easy it is )

Step-by-step explanation:

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Please helpppp???????????​
Temka [501]

Step-by-step explanation:

I think 360-175 iam not sure

4 0
3 years ago
What’s the answer to 10(x-2)-3 (x+3)
Svetlanka [38]

Answer:7x-29

Step-by-step explanation: simplify and open the brackets.remember that a letter and a number cannot be sumed up but can my multipled together

5 0
3 years ago
Carson bought a coat for 40% of the original price, then another 15% off the discounted price. If the coat originally cost $149,
irinina [24]
Answer: $75.99

Steps: 149×0.6= 89.4
Multiply 89.4×0.85= 75.99

Hope this helps ʕ•ᴥ•ʔ
5 0
3 years ago
Which statement about the zeros of the graphed function is true?
Anton [14]

Answer:

A. The function has three distinct real zeros.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
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