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maw [93]
3 years ago
13

Enter the missing values in the area model to find 8(8k + 9)

Mathematics
2 answers:
Digiron [165]3 years ago
7 0
64k for the two eights and 9. The answer to the bottom is 64k+72.

Vika [28.1K]3 years ago
3 0
8(8k+9) = 64k+72 , hope this helped :)
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One hundred eighty is equal to how many tens
Nadya [2.5K]
There are 18 tens in 180 because if you divide 180 divided by 10, you get 18. you can also do it in your head!!! 
Hope this helps!!!
5 0
3 years ago
Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len
Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em>   ==>   d<em>y</em>/d<em>t</em> = -2

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\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt

=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt

=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt

=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}

5 0
3 years ago
What time is 5 3/4 hours after 11:32 pm?
elixir [45]

11:32 pm + 5 hours= 4:32pm

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3/4 hour = 45 min


6 0
3 years ago
Read 2 more answers
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Afina-wow [57]
Find a common denominator which is 12

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3 0
3 years ago
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weqwewe [10]

F(180) = x/30

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5 0
3 years ago
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