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Deffense [45]
2 years ago
7

What is the answer to 5(–2 − 4d) =

Mathematics
2 answers:
vlada-n [284]2 years ago
7 0

Answer: -10+20d

Step-by-step explanation: I distributed(multiplied) 5 to -2 and 4d. This would equal out to -10 and 20. This is in the simplest form! Hope this helped.

Mariana [72]2 years ago
5 0
-10-20d that’s the answer
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Only do question 4<br><br> 50 points<br><br> Topic: Percentage
Sergeu [11.5K]

Answer:

a 1

b 6

c 15

Step-by-step explanation:

101% 101/100 = 1 1/100

is 1  complete 100 grid and 1/100 of another grid so you will need 2 grids

589% 589/100 = 5 89/100

is 5 complete 100 grids and 89/100 of another grid so you will need 6 grids

1450% 1450/100 = 14 50/100

is 14 complete grids and 50/100 of another grid so you will need 15 grids

4 0
3 years ago
I need this asap pleasee!
miv72 [106K]

Answer:

The answers are below

Step-by-step explanation:

The greater sign is > and the less then symbol is <

Using the red arrows on the number line, you can tell which one is bigger or less. The dot is colored in so it has to have a line under it. So for the first one (top, left), The red arrow is pointing to the right side meaning x is bigger than 3. Therefore x ≥ 3.

In the next one (top, right) the arrow is pointing to the negative side so that one must be less than 3. The dot is also colored in meaning it is: x ≤ 3

In the next one (bottom, left) the arrow is pointing to the right, the dot not colored in, so it has no line. Therefore it is  x > 3

Last one (bottom right) the arrow is pointing left, dot is white meaning that the answer is x < 3

If you're wondering what the open dots and closed dots mean:

An open dot is used to show that the ray's endpoint is not a component of the solution when the inequality is "strict" ( < or >).

A closed dot is used to denote that the endpoint is a component of the solution for the other types of inequalities (≥ and ≤ ).

6 0
2 years ago
Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (
Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

(c) 209 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138    (1)

The second equation in the unknowns is

3B + 5N = 71  (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===>   40B + 30N = 690   (3)

Multiplying (2) by 6 ===>  18B + 30N = 426    (4)

(3) - (4) eliminates the N variables and yields

22B = 264   ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==>  36 + 5N = 71 ==> 5N = 71-36 = 35 ==>  N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

(c) If we add both equations (1) and (2), we get

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0
1 year ago
I need help pls it’s a final
algol [13]

Answer:

A.Both of the students did the problem correctly.

Step-by-step explanation:

B. Nikki multiplied the fraction(8/3) to the items in the parentheses. Then multiplied each side with 3. Jon did the opposite. He first removed the fraction by multiplying each side by 3. Then he multiplied 2 to the items in the paranthesis.

C. I prefer Jon's method. Fractions can be tricky. I prefer to remove them as soon as possible. This time the items in the paranthesis had whole numbers. But had any of them been a fraction too, the problem would have gotten a lot more tricky and it would very easy to make a mistake or miscalculate something.

6 0
3 years ago
Read 2 more answers
How many different 13 card bridge hands can be selected from an ordinary deck?
amm1812
Your answer would be <span>635013559600.
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