Answer:
First choice:

Explanation:
<em>The probability that the first is a man's card and the second, a woman's card</em> is calculated as the product of both probabilities, taking into account the fact that the second time the number of cards in the hat has changed.
In spite of it is said that the cards are drawn at once, since it is stated a specific order for the cards (first is a man's card and the second, a woman's card) you can model the procedure as if the cards were drawn consecutively, instead of at once.
<u>1. Probability that the first is a man's card</u>
- Number of cards in the hat = 20 (the 20 business card)
- Number of man's card in the hat: 10
- Probability = favorable oucomes / possible outcomes = 10/20 = 1/2.
<u />
<u>2. Probability that the second is a woman's card</u>
- Number of cards in the hat = 19 (there is one less card in the hat)
- Number of wonan's card in the hat: 10
- Probability = favorable oucomes / possible outcomes = 10/19.
<u>3. Probability that the first is a man's card and the second, a woman's card</u>
<u />
That is the first choice.
Yes because 3×2= 6 , 3×5= 15, 15 + 6 = 21
Answer:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of normal variable:
Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is
and the standard deviation is 
Calls to a customer service center last on average 2.8 minutes.
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day
This is M, so:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Answer:
The first one
Step-by-step explanation:
The decimals line up when you subtract them
9514 1404 393
Answer:
C. 13
Step-by-step explanation:
Put 4 where y is in the equation and do the arithmetic.
