Answer:
Remember, a number a is a zero of the polynomial p(x) if p(a)=0. And a has multiplicity n if the factor (x-a) appear n times in the factorization of p(x).
1. Since -2 is a zero with multiplicity 1, then (x+2) is a factor of the polynomial.
2. Since 1 is a zero with multiplicity 2, then (x-1) is a factor of the polynomial and appear 2 times.
3. Since 5 is a zero with multiplicity 3, then (x-5) is a factor of the polynomial and appear 3 times.
Then, the polynomial function with the zeros described above is

9^2 × 9^6=9^10/9^2
When multiplying exponents, if the bases are the same you add the exponents.
9^2 × 9^6 = 9^(2+6)=9^8
When dividing exponents, I'd the bases are the same you subtract the bottom exponent from the top.
9^10/9^2=9^(10-2)=9^8
9^8=9^8
Solution: 9^10 over 9^2
The value of x is 5 since 5^2=25+2=27/3=9
Answer:
B) 7/25
Step-by-step explanation:
sin M = opposite/hypotenuse = 7/25