Answer:
I should be able to do this because im in 6th grade...
Step-by-step explanation:
Answer:
224 feet^3
Step-by-step explanation:
Cube -> Volume = 4×7×7 = 196 feet^3
Prism -> Volume = 2×7×2 = 28 feet^3
196+28=224
Answer:
<u>Circumference</u><u> </u><u>of </u><u>a </u><u>circle </u><u>is </u><u>given </u><u>by </u>
<u></u>
- Given - <u>Diameter</u><u> </u><u>of </u><u>circle </u><u>=</u><u> </u><u>1</u><u>0</u><u> </u><u>yards</u>
now ,
<u>substituting</u><u> </u><u>the </u><u>value </u><u>of </u><u>r </u><u>in </u><u>the </u><u>formula </u><u>of </u><u>circumference</u><u> </u><u>~</u>
hope helpful :D
Answer:
x = 10
Step-by-step explanation:
Use CPCTC (Corresponding parts of congruent triangles are congruent).
Set the ratios:
First, simplify. Combine like terms:
Next, cross multiply.
Isolate the variable, x. Divide 6.5 from both sides of the equation:
Check:
Plug in 10 for x (Your answer). Cross multiply, then simplify:
(True).
~
Step-by-step explanation:
a. The null hypothesis is generally an exact value and the alternative hypothesis is the one we are trying to show. We are trying to show that the population mean is different from $24.57, so the hypotheses are as follows:
Null: The population mean hourly wage in the manufacturing industry is the same as the population mean hourly wage in the goods-producing industries
Alternative: The population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries
b.
Because we know the population standard deviation, we can use a z test
Plugging in the values:
Expected population mean: 24.57
Sample average: 23.89
Sample size: 30
Population standard deviation: 2.4, we get 0.1207 as our p-value.
c. Using a = 0.05, our p-value is greater than that, so we can not conclude the alternative hypothesis (The population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries)
d. Using a critical value calculator, we can find that for a two-tailed approach, the critical value would be 1.96. This would mean that the z score would have to be greater than 1.96 or less than -1.96 for the results to be significant. The population mean we would plug in here is 24.57, while the raw score would be 23.89 and the standard deviation would be 2.4. The z score we get is -0.283, which is not in the values specified (>1.96 or <-1.95) so we cannot conclude the alternative hypothesis