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xz_007 [3.2K]
3 years ago
12

−8x + 3y = 21 solve it

Mathematics
2 answers:
Nataly [62]3 years ago
6 0
So first we have to subtract 3y from 21 cause the oppisit of addition which is subtraction so you get 18y when we divide that with -8y and get y=2.25y
tamaranim1 [39]3 years ago
5 0
-8x + 3y = 21
-8x + 8x + 3y = 21 + 8x
<u>3y</u> = <u>21 + 8x</u>
 3          3
  y = 7 + 2 2/3x
-8x + 3(7 + 2 2/3x) = 21
-8x + 21 + 8x = 21
-8x + 8x + 21 = 21
0x + 21 = 21
0x + 21 - 21 = 21 - 21
<u>0x</u> = <u>0</u>
 0     0
  x = 0
-8(0) + 3y = 21
0 + 3y = 21
<u>3y</u> = <u>21</u>
 3      3
  y = 7
(x, y) = (0. 7)
-----------------------------------------------------------------------------------------------
-8x + 3y = 21
-8x + 3y - 3y = 21 - 3y
<u>-8x</u> = <u>21 - 3y</u>
 -8         -8
   x = -2 5/8 + 3/8y
-8(-2 5/8 + 3/8y) + 3y = 21
21 - 3y + 3y = 21
21 - 0y = 21
21 - 21 - 0y = 21 - 21
<u>-0y</u> =<u> 0</u>
 -0    -0
   y = 0
-8x + 3(0) = 21
-8x + 0 = 21
<u>-8x</u> = <u>21</u>
 -8     -8
   x = -2 5/8
(x, y) = (-2 5/8, 0)
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The general term for the sequence 2, 4, 8, 16, 32, . . . is
Nuetrik [128]

We are given

sequence is 2 , 4 , 8 ,16 , 32 , .....

Firstly , we will check whether it is geometric sequence

Checking geometric sequence:

We will find common ratio between successive terms

and then we check whether they are equal

r1=(second term)/(first term)

r_1=\frac{4}{2}=2

r2=(third term)/(second term)

r_2=\frac{8}{4}=2

r3=(fourth term)/(third term)

r_3=\frac{16}{8}=2

r4=(fifth term)/(fourth term)

r_4=\frac{32}{16}=2

we can see that all four ratios are same

r_1=r_2=r_3=r_4=2

so, this is geometric sequence

Calculation of general term:

We got

common ratio is

r=2

Let's assume

number of terms is n

first term is 2

a_1=2

now, we can use formula

a_n=a_1 (r)^{n-1}

we can plug values

and we get

a_n=2(2)^{n-1}

a_n=2^1(2)^{n-1}

a_n=(2)^{n-1+1}

a_n=(2)^{n}..................Answer


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