Answer:
Option 1,
The triangle MNP is similar to the triangle with side lengths 35 cm, 41 cm, 43 cm
Step-by-step explanation:
Given triangle MNP has side lengths 3.5 cm, 4.1 cm, and 4.3 cm. we have to find the similarity triangle sides from the given option.
As we know, the two triangles are similar if the measures of the corresponding sides of two triangles are proportional.
For the first option: 35 cm, 41 cm, 43 cm
which shows that the sides are proportional.
we have to choose only one option ∴ we needn't have to check the others
Hence, the triangle MNP is similar to the triangle with side lengths 35 cm, 41 cm, 43 cm
Hello.
is a quadratic function, because it has an 
(x squared, or x times x) term.
Here's what linear functions look like:
A graph of a linear function is a line.
Quadratic functions look like so:
A graph of a quadratic function is a parabola.
Therefore, the given function is a quadratic function.
I hope this helps.
Have a nice day.
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer:
16+16
32
Step-by-step explanation:
Let's assume
height of plane in feet =h
time in minutes =t
we are given
A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet
so, we get one point as (5,6500)
After 7 minutes it is at a height of 5900 feet
so, we get another point as (7,5900)
we can use point slope form of line
points as
(5,6500)
x1=5, y1=6500
(7,5900)
x2=7 , y2=5900
Calculation of slope(m):
now, we can plug values
Equation of line:
we can use formula
we can plug values
Time of landing:
we can set h=0
and then we can solve for t
..............Answer
