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kolbaska11 [484]
4 years ago
9

What is 12 14/15 as a decimal

Mathematics
2 answers:
Lina20 [59]4 years ago
8 0
12.9333 Its easy to convert a fraction to a decimal then just add the 12 as a whole number
timama [110]4 years ago
3 0

Answer:

12.93 with a line above the three

Step-by-step explanation:

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Triangle MNP has side lengths 3.5 cm, 4.1 cm, and 4.3 cm. A triangle with what side lengths would be similar to triangle MNP?
atroni [7]

Answer:

Option 1,

The triangle MNP is similar to the triangle with side lengths 35 cm, 41 cm, 43 cm

Step-by-step explanation:

Given triangle MNP has side lengths 3.5 cm, 4.1 cm, and 4.3 cm. we have to find the similarity triangle sides from the given option.

As we know, the two triangles are similar if the measures of the corresponding sides of two triangles are proportional.

For the first option: 35 cm, 41 cm, 43 cm

\frac{3.5}{4.1}=\frac{4.1}{41}=\frac{4.3}{43}=\frac{1}{10}

which shows that the sides are proportional.

we have to choose only one option ∴ we needn't have to check the others

Hence, the triangle MNP is similar to the triangle with side lengths 35 cm, 41 cm, 43 cm

6 0
3 years ago
What type of function is y=x^2+6x+5
nata0808 [166]

Hello.

\mathrm{y=x^{2} +6x+5} is a quadratic function, because it has an \mathrm{x^{2} } (x squared, or x times x) term.

Here's what linear functions look like:

\mathrm{y=mx+b}

A graph of a linear function is a line.

Quadratic functions look like so:

\mathrm{y=ax^{2} +bx+c}

A graph of a quadratic function is a parabola.

Therefore, the given function is a quadratic function.

I hope this helps.

Have a nice day.

\boxed{imperturbability}

3 0
3 years ago
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
3 years ago
Pls find area of this shape
Basile [38]

Answer:

16+16

32

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590
Jet001 [13]

Let's assume

height of plane  in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

y-y_1=m(x-x_1)

points as

(5,6500)

x1=5, y1=6500

(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug values

m=\frac{5900-6500}{7-5}

m=-300

Equation of line:

we can use formula

y-y_1=m(x-x_1)

we can plug values

h-6500=-300(t-5)

h=-300t+8000

Time of landing:

we can set h=0

and then we can solve for t

h=-300t+8000=0

t=\frac{80}{3}min..............Answer

5 0
4 years ago
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