Answer:
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Step-by-step explanation:
sorry
Vertices (3,0),(-3,0) co-vertices (0,-5),(0,5)
transverse axis (line passing vertices) is on(or parallel to) x-axis then formula is
(x-h)^2/a^2 - (y-k)^2/b^2 = 1
..notice.. x^2 is on positive / y^2 is on negative
center (h,k) is midway between vertices = (0,0)
we have h = k = 0 and now formula is
x^2/a^2 - y^2/b^2 = 1
a is the distance from a vertex to center = 3
b is the distance from a co-vertex to center = 5
the formula is
x^2/3^2 - y^2/5^2 = 1 ... answer is the 1st
I dont really know maybe use the diagram it might help a lil
The function is

Initial investment is given when

, so substituting this into

we have


Hence, correct answer is B $10
Using log rules:
when you divide and then sperate you subtract.
So
Log3(5/x^2) would be A
Log3(5)-Log3(x^2)