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2 years ago

12

Hilary is making slime for a class project

1 answer:

Fynjy0 [20]2 years ago

5 0

4:6
8:12
Are the answers

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A circle is shown. Secant X Z and tangent W Z intersect at point Z outside of the circle. Secant X Z goes through the center of

andriy [413]

Answer:

16

Step-by-step explanation:

7 0

3 years ago

8 ÷ 1/3 I forgot how to do this please help me

Olegator [25]

Simplify the following:
8/(1/3)

Multiply the numerator of 8/(1/3) by the reciprocal of the denominator. 8/(1/3) = (8×3)/1:
8×3

8×3 = 24:
Answer: 24

5 0

3 years ago

Read 2 more answers

Phantasy [73]

Hi there! You are provided with two points, this is all you need to calculate the line's slope.

The equation for slope is:

$\frac{y2 - y1}{x2 - x1}$

$\frac{10 - 8}{3 - 7} = -\frac{2}{4}$

Slope: -2/4

Point slope form, or y-y1 = m(x - x1). All we have to do is take the x and y coordinates of either point, as well as the slope, and plug them into the equation.

y - 10 = -2/4(x - 3)

Write the equation in slope-intercept form (y=mx+b)

$y - 10 = -2/4(x-3)\\y = -2/4(x-3) + 10\\y = -2/4x + 1.5 + 10\\y = -2/4x + 11.5$

A) -2/4

B) y - 10 = -2/4(x - 3)

C) y = -2/4x + 11.5

8 0

3 years ago

Alice and Claire go apple picking. When they are done, Claire has 3 times as many apples in her basket as Alice has in hers. (No

ElenaW [278]

Answer:

6 apples, 21 apples, 30 apples respectively

Step-by-step explanation:

Let us first start by writing <u>expressions</u> so that we can easily solve for the problems below.

Let us suppose Alice is x. In this case, Claire has 3 times Alice's apples, so 3x.

1. If Alice has 2 apples (x), then Claire has 3x

3*2=<u>6 apples</u>

Claire has 6 apples.

2. If Alice has 7 apples (x), then Claire has 3x

3*7=<u>21 apples</u>

Claire has 21 apples.

<u />

3. If Alice has 10 apples (x), then Claire has 3x

3*10=<u>30 apples</u>

Claire has 30 apples.

<em>I hope this helps! Please let me know if you have any further questions :)</em>

5 0

3 years ago

I need to get the left side to equal the right side. Keeping the right side alone and not changing it.

likoan [24]

<u>To prove the trigonometric equation:</u>

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

$RHS=(\sin x+\cos x)(1-\sin x \cos x)$

We know that $\sin^2x +\cos^2x=1$ , substitute this in place of 1.

$=(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)$

Multiply each term of the first term with each term of the 2nd term.

$=\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x$

Group like terms together.

$=\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x$

$=\sin^3x +( 0)+(0) + \cos^3 x$

$=\sin^3x + \cos^3 x$

= LHS

RHS = LHS

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

Hence proved.

7 0

3 years ago