If I'm doing it wrong correct me please but can you finish the rest for me idk how to

Results from previous studies showed 76% of all high school seniors from a certain city plan to attend college after graduation.

Degger [83]

Answer:

Yes, this indicate that the percentage has increased from that of previous studies.

Step-by-step explanation:

We are given that Results from previous studies showed 76% of all high school seniors from a certain city plan to attend college after graduation.

A random sample of 200 high school seniors from this city reveals that 162 plan to attend college.

Let p = % of all high school seniors from a certain city who plan to attend college after graduation

SO, Null Hypothesis, $H_0$ : p $\leq$ 76% {means that the percentage has not increased from that of previous studies}

Alternate Hypothesis, $H_a$ : p > 76% {means that the percentage has increased from that of previous studies}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of high school seniors from this city who

plan to attend college = $\frac{162}{200}$ = 0.81

n = sample of high school seniors = 200

So, test statistics = $\frac{0.81-0.76}{{\sqrt{\frac{0.81(1-0.81)}{200} } } } }$

= 1.8025

Now at 5% significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the percentage has increased from that of previous studies.

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hey you,the answer is 'B'

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