Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male

Step-by-step explanation:
<u>Explanation</u>:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
<em>Let 'B' be the event of brown eyes </em>
<em>Total number of males n(M) = 33</em>
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>
<em></em>
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<em>From table the brown eyes from males = 10</em>


<u>Final answer</u>:-
The probability that a randomly selected student from the class has brown eyes , given they are male

Answer: 11/12
Step-by-step explanation:
1. To solve this problem you can transform the mixed numbers given in the problem to fractions, as you can see below:
3 2/3=(3*3+2)/3=11/3
2 3/4=(4*2+3)/4=11/4
2. Now you must make the substraction of the fraction:
11/3-11/4=11/12
3. Therefore, the answer is 11/12
Answer:
.
Step-by-step explanation:
Given the statement
If
, then E and F are mutually exclusive events.
If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.
Therefore, the statement is always true as P(E∩F)=0
For mutually exclusive events:
.
Answer:
both on the left
Step-by-step explanation: