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ser-zykov [4K]
3 years ago
14

Find the area. Simplify your answer. 2x-2 3x​

Mathematics
2 answers:
suter [353]3 years ago
5 0

Answer:

i think 5x^2-5

Step-by-step explanation:

(3X)(2X-2)

5X^2-5

Hatshy [7]3 years ago
4 0

Answer:

im pretty sure its 5×^2-2

Step-by-step explanation:

im not sure but don't take my word for it

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How many hoursarea180minub
Dafna11 [192]
Solutions 

1hr = 60 min

180 ÷ 60 = 3 

<span>180 min = 3 hrs </span>
7 0
3 years ago
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I have tree pizzas. The radius of one pizza is 4 inches. The radius of the second pizza is 8 inches. The radius of the last pizz
pav-90 [236]
10? Yea I think 10 is the answer
3 0
2 years ago
Will give brainliest <br> What is the output of y=6x−11 when the input is 5?
MrRissso [65]

Answer:

19

Step-by-step explanation:

y = 6x - 11     If x = 5

y = (6*5) - 11

y = 30 - 11

y = 19

5 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
I NEED HELP ASAP PLEASE!!!
Alex17521 [72]

Answer:

Q2: -17

Q3: a) -5/2  b) g = -13

Step-by-step explanation:

2w+7 = -9

2w = -9 - 7

w = -16/2

w = -8

---

15 - 4w

= 15 - 4(-8)

= 15 - 32

= -17

----------------------

Q3:

a) 3/4(16m-24) = -48

16m -24 = -48 ÷ 3/4

16m = -64 + 24

16m = -40

m = -5/2

b) -20 = 1/6(36+12g)

-20 = 1/6 × 6(6+2g)

(cross out the 6 from 1/6 and 6)

-20 = 6 + 2g

-20-2g= 6

-2g = 6+20

-2g = 26

g = 26/-2

g = -13

3 0
3 years ago
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