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Yanka [14]
3 years ago
7

Tia performed an experiment where she flipped a coin 200 times. The coin landed heads up 92 times and tails up 108 times. Which

statement about this experiment is true?
The ratio StartFraction 92 over 200 EndFraction represents the experimental probability of the coin landing heads up in this experiment.
The ratio StartFraction 92 over 200 EndFraction represents the number of trials in this experiment.
The ratio StartFraction 92 over 200 EndFraction represents the theoretical probability of the coin landing heads up in this experiment.
The ratio StartFraction 92 over 200 EndFraction represents the number of occurrences of the coin landing heads up in this experiment.
Mathematics
2 answers:
Olegator [25]3 years ago
7 0

Answer:

The ratio StartFraction 92 over 200 EndFraction represents the theoretical probability of the coin landing heads up in this experiment.

Step-by-step explanation:

..

ra1l [238]3 years ago
3 0

Total number of times she flipped a coin =200.

Total number of heads in the experiment=92

Total number of tails in the experiment=108

Therefore probability of the coun landing heads up in this experiment is 0.5

In the above experiment, the probability of the coin landing heads up is

P(H)= 92/200 = 0.46

In the above experiment, the probability of the coin landing tails up is P(T) = 108/200 = 0.54

The ratio obj represent the experimental probability of the coin landing heads up in this experiment

Therefore the correct option is 1.

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Read 2 more answers
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
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Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

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The width of the garden to be built in the yard = Uniform width

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The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

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The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

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When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

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