Answer:
scale factor is 3, k=3
Step-by-step explanation:
everything is being multiplied by 3
Answer:
D
Step-by-step explanation:
given the 2 equations
x + 2y = 27 → (1)
2x + 3y = 46 → (2)
Rearrange (1) expressing x in terms of y by subtracting 2y from both sides
x = 27 - 2y ← substitute into (2)
2(27 - 2y) + 3y = 46
54 - 4y + 3y = 46
54 - y = 46 ( subtract 54 from both sides )
- y = - 8 ( multiply both sides by - 1 )
y = 8 → D
Answer:
$15,360
Step-by-step explanation:
To find the retail price, multiply 12,800 by 1.2
12,800(1.2)
= 15,360
So, the retail price is $15,360
Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation

Solve for S(t):


The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:



There's no sugar in the water at the start, so (a) S(0) = 0, which gives

and so (b) the amount of sugar in the tank at time t is

As
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.