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liubo4ka [24]
3 years ago
14

A bus is a box a volume of 2520 cubic feet. If the bus is 35 feet long by 8 feet wide, what is the height of the bus

Mathematics
1 answer:
AysviL [449]3 years ago
3 0

Answer:

9 feet

Step-by-step explanation:

multiply 35x8 which equals 280 then divide 2520÷280=9

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HELP HURRY pls
Bess [88]

Please see the explanation of this question to see procedure for the dilation of the triangle ABC and the image attached below to know the result.

<h3>How to generated a resulting triangle by transformation rules</h3>

In this question we must apply a kind of <em>rigid</em> transformation known as dilation. A dilation of a point around a point of reference is defined by the following operation:

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]     (1)

Where:

  • O(x, y) - Point of reference
  • k - Dilation factor
  • P(x, y) - Original point
  • P'(x, y) - Resulting point

Let assume that the point P is the origin of a <em>rectangular</em> system of coordinates. Then, the coordinates of the three vertices of the triangle ABC respect to the origin are: A(x, y) = (- 1, 2), B(x, y) = (- 1, - 1), C(x, y) = (2, 0).

Then, the vertices of the resulting triangle A'B'C' are, respectively:

A'(x, y) = (0, 0) + 3 · [(- 1, 2) - (0, 0)]

A'(x, y) = (- 3, 6)

B'(x, y) = (0, 0) + 3 · [(- 1, - 1) - (0, 0)]

B'(x, y) = (- 3, - 3)

C'(x, y) = (0, 0) + 3 · [(2, 0) - (0, 0)]

C'(x, y) = (6, 0)

Finally, we draw the resulting triangle with the help of a graphing tool.

To learn more on dilations: brainly.com/question/13176891

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7 0
2 years ago
A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,
slavikrds [6]

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is \frac{1}{2}, in the second is \frac{1}{4}, in the third is \frac{1}{8} and so on. Then, P(C) is given by the next sum:

P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1

This is a geometric series with factor \frac{1}{2}. Then is convergent to \frac{1}{1-\frac{1}{2}}-1=1.. With this we have proved that P(C)=1.

Now, observe that

P(H)=\frac{1}{2}, P(TH)=\frac{1}{4},P(TTH)=\frac{1}{8},P(TTTH)=\frac{1}{16},P(TTTTH)=\frac{1}{32},P(TTTTTH)=\frac{1}{64}.

Then

P(C1)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} =\frac{31}{32}

P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}

P(C1\cap C2)=P(TTTTH)=\frac{1}{32}

and

P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B162%7D%20" id="TexFormula1" title=" \sqrt[3]{162} " alt=" \sqrt[3]{162} "
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Answer:

n

Step-by-step explanation:

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a

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this is because it is right

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