Please help thanks guys

Of a total of 6,000.00, part was invested at a simple interest rate of 8% and part at 7% if the total interest income for one ye

alekssr [168]

Answer: Ok so first 0.05(6000 - x) + 0.07x = 372

300 - 0.05x + 0.07x = 372

300 + 0.02x = 372

0.02x = 72

x = 3600

He invested $3600 at 7% and $2400 at 5%.

<h2>Hope this helps have a bless day❤️</h2>

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Roll the number cube to find the observed frequency. Which statements are true? Check all that apply

ch4aika [34]

Answer:

(a) and (c)

Step-by-step explanation:

Given

See attachment for complete question

Required

Select all true statements

First, calculate the total observed frequency;

$Total = 11 + 16 + 14 + 20 + 12 + 17$

$Total = 90$

(a): Relative frequency of 4 is 2/9

Relative frequency is calculated by:

$RF= \frac{Observed\ Frequency}{Total}$

For roll 4

$Observed\ frequency = 20$

So, the relative frequency is:

$RF = \frac{20}{90}$

Simplify

$RF = \frac{2}{9}$

(a) is true

(b): Experimental probability of 3 greater than its theoretical probability

The experimental probability is its relative frequency;

For roll 3

$Observed\ frequency = 14$

The experimental probability is:

$Pr = \frac{14}{90}$

Simplify

$Pr = \frac{7}{45} = 0.156$

To calculate the theoretical probability, w have:

$S = \{1,2,3,4,5,6\}$ ---- sample space

$n(S)= 6$

$n(3) = 1$ --- number of times 3 occur

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The theoretical probability is $greater\ than\ the$ experimental probability.

(b) is false

(c): Experimental probability of 2 greater than its theoretical probability

Using the explanations in (b), we have:

For roll 2

$Observed\ frequency = 16$

The experimental probability is:

$Pr = \frac{16}{90}$

Simplify

$Pr = \frac{8}{45} = 0.178$

To calculate the theoretical probability, we have:

$n(S)= 6$

$n(2) = 1$

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The experimental probability is $greater\ than\ the$ theoretical probability.

(c) is true

(d): Relative frequency of 5 is 2/13

For roll 5

$Observed\ frequency = 12$

The relative frequency is:

$RF = \frac{12}{90}$

Simplify

$RF = \frac{2}{15}$

(d) is true

7 0

2 years ago

Help me please, need this done now.

Nikolay [14]

simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Step-by-step explanation:

We need to simplify: $\frac{\sqrt{4}}{\sqrt[3]{4}}$

Solving:

$\frac{\sqrt{4}}{\sqrt[3]{4}}$

We know that √ = 1/2 and ∛=1/3

$\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}$

So, simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

6 0

2 years ago

The sum of three integers is 12

Liula [17]

The three integers are 5,17 and -10

Step-by-step explanation:

Let x, y and z be three integers then

$x+y+z=12 \ \ \Eqn\ 1$

'The sum of the first and second integers exceeds the third by 32'

$x+y=z+32\ \ \ \ Eqn\ 2$

The third integer is 15 less than the first.

$z=x-15\ \ \ \ Eqn\ 3$

From Eqn 2:

$x+y=z + 32\\x+y-z=32$

Subtracting Eqn 1 from eqn 2

$x+y-z-(x+y+z)=32-12\\x+y-z-x-y-z=20\\-2z=20$

Dividing both sides by -2

$\frac{-2z}{-2}=\frac{20}{-2}\\z=-10$

Putting z=-10 in Eqn 3

$z=x-15\\-10=x-15\\x=15-10\\x=5$

Putting x=5 and z=-10 in Eqn 1

$x+y+z=12\\5+y-10=12\\y-5=12\\y=12+5\\y=17\\$

Hence,

The three integers are 5,17 and -10

Keywords: Linear Equations, Variables

Learn more about linear equations at:

#LearnwithBrainly

3 0

2 years ago

Read 2 more answers

I need help with the question

sweet [91]

Answer:

B

Step-by-step explanation:

Comment

√15 = 3.87

√12 = 3.46 Subtract these 2

Difference = 0.41

5 0

5 months ago