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3 years ago

What is the determinant of k= 6 8 0 3

Mathematics

2 answers:

zmey [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Kamila [148]3 years ago

4 0

Answer is 18

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Then pls mark as brainliest

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What is the area of the figure below?

murzikaleks [220]

96m^2 is your answer

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3 years ago

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Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

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3 years ago

100 POINTS!!!!!!!!! ANSWER NOW<br><br><br>Evaluate each exponent.

Aleonysh [2.5K]

Answer: $-3^4=-81\\(-3)^4=81\\3^{-4} =\frac{1}{81} \\-3^{-4} =-\frac{1}{81}$

Step-by-step explanation: In some cases you must apply the exponent rule, simplify, or multiply them together to get your answer.

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2 years ago

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Help with one last math question <br> thank u

Vitek1552 [10]

It has to be the last one, D. I did it over 3 times to make sure.

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3 years ago

Brainliest pls help (dont have to show work)

Kitty [74]

Answer:

-2.35

Step-by-step explanation:

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3 years ago