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Greeley [361]
3 years ago
5

A phone call starts at 9:14a.m. the call lasts for 24 minutes. what time does the call end?

Mathematics
2 answers:
MrRissso [65]3 years ago
5 0
10:28 pls mark brainless .
madam [21]3 years ago
3 0

Answer:

It would end at 9:38

Step-by-step explanation:

but obviously it is not one of the answer choices, so I would go with 9:42

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Find the length of the third side. If necessary, write in simplest radical form.
soldier1979 [14.2K]

Answer:

the same way Pythagoras Theorem

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2 years ago
Find the with of a triangle as a 15 cm high in a hypogynous of a 19 cm​
Inessa05 [86]

Answer:

This other side of the triangle is equal to about 11.7 cm

Step-by-step explanation:

In order to find out the third side of the triangle we will just use the Pythagoras Theorem.

c^{2} =a^{2} + b^{2}

Since we know the hypotenuse and we know one of the legs, in order to find the second leg we just substitute the values and solve the equation and so we get...

c^{2} =a^{2} + b^{2}\\19^{2} = 15^{2} + b^{2}\\361 = 225 + b^{2} \\

b^{2} = 361 - 225\\b^{2} = 136\\b = \sqrt{136} \\

And so b ≈ 11.66190

8 0
3 years ago
Find the midpoint of the line segment with the given endpoints (-3,1 -2,8) (-4.92,-3.3)
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(1,1) , (3,3)
(2,4), (-3,-3)
6 0
3 years ago
Write the ratio<br> 2/3 /5<br> in simplest form
Ierofanga [76]

Answer:

A) 2/15

Step-by-step explanation:

So just divide it normally, do keep change flip

2/3*1/5

2/3 keep

divison change

Denomeinator, flip it, 5 to 1/5

now multiply

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5 0
3 years ago
What is the area of this figure?<br> Use 3.14 for TT.<br><br> Please help
german

Answer:

406.08

Step-by-step explanation:

First FInd the area of the rectangle : which is short side * long side

-> 15*12=180m

Then find the area of the half circle, the formula of the area of a circle is \pi r^2

here it's half a circle so it's \frac{\pi r^2}{2} where r is 12

-> 3.14\cdot \frac{\left(12\right)^2}{2}=226.08 m

Finally just add the area of the rectangle with the area of the half circle

-> 180+226.08=406.08 m

5 0
2 years ago
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